many ... any number x so that (x+2)/x, x>2
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If the divisor of a division problem is 4, any number between 0 and 3 (inclusive) can be a remainder for that problem.
remainder
Yes there is. The real problem is just inverting the remainder into the decimal for the answer.
1. The divisor is the second number in a division problem. For instance 6 / 3 = 2. In this example, the divisor is 3. If you have a divisor of X, then the largest remainder possible is X-1. This is because if you had one more number in the remainder, it would form a complete count, and the remainder would go away. In the case of 2 as your divisor, think of the number 11. 11 / 2 has a remainder of 1. However, if you had one more in the remainder, you'd have 2, and that would be a complete division. (Also, the number you have to be 12.) And there would be no remainder.