The median of 65 and 90 is the same as their mean: 77.5The median of 65 and 90 is the same as their mean: 77.5The median of 65 and 90 is the same as their mean: 77.5The median of 65 and 90 is the same as their mean: 77.5
The answer depends on what variable you are looking at: the sum, the product, the maximum, mean, median, range, and so on. The odds will be different.
If you mean chosing both cards - the odds are 1 in 169. If you mean chosing either a king or a queen - the odds are 1 in 13
The mode, median, and range of a single data point such as 65 are all the data point itself, 65 in this instance.
3
Your "odds" are your likelihood or probability of winning.
The odds of not drawing a 6 from a standard deck of 52 cards is 48 in 52, or about 0.9231.
-Opposites of evens. -odds can also mean the chances of something happening.
probabilidades
The median of 65 and 90 is the same as their mean: 77.5The median of 65 and 90 is the same as their mean: 77.5The median of 65 and 90 is the same as their mean: 77.5The median of 65 and 90 is the same as their mean: 77.5
I think this is a Texas hold 'em question. The odds are about 57% in favour of the two kings for the AQ, and about 65% for the kings against the A9
it means odds ratio
Being "at odds" with someone means disagreeing or quarrelling with that person. "At odds" indicates some kind of variance or conflict. One can even be "at odds" with oneself, struggling over an internal conflict.
For 2 to 39 odds of winning;Probability of winning:0.95122, or;Chance of winning:95.12%
Odds of 9-2 means that for every 2$ you bet you will get 9$ if you win, and nothing otherwise.
The answer is 493
I suppose you mean, the couple already has 2 girls. In this case, the odds are about 50%. If the couple already has 6 boys and no girls, the odds are about 50%. If the couple has a boy and a girl, the odds are about 50. If the couple doesn't have children yet, the odds are about 50%.