The mode, median, and range of a single data point such as 65 are all the data point itself, 65 in this instance.
Mean: 67.143 Median: 78 Mode: 56, 78, 85, 92, 65, 79, 15 Range: 77
Range: 24 Median: 59.5 Mode: 57, 61, 58, 54, 68, 51, 65, 75
The median of 65 and 90 is the same as their mean: 77.5The median of 65 and 90 is the same as their mean: 77.5The median of 65 and 90 is the same as their mean: 77.5The median of 65 and 90 is the same as their mean: 77.5
Median is 70 The median is the middle number once you have reordered the sequence (therefore, 72 is not the median). The mode is the most common number The mean is the average.
One possible data set is {100, 100, 100, 20, 30, 40}, where the mode is 100 (as it appears most frequently), the mean is 100 (sum is 390, divided by 6 gives 65), and the median is 100 (the average of the third and fourth values, which are both 100). Another data set could be {100, 100, 100, 10, 20, 30}, also with a mode of 100, a mean of 65 (sum is 360), and a median of 100. In both cases, the mean is less than the median.
Alright, buckle up, buttercup. The mean is 65.43, the median is 65, the mode is 56, and the range is 20. So, there you have it. Math never looked so sassy.
Mean: 67.143 Median: 78 Mode: 56, 78, 85, 92, 65, 79, 15 Range: 77
Range: 24 Median: 59.5 Mode: 57, 61, 58, 54, 68, 51, 65, 75
The median of 65 and 90 is the same as their mean: 77.5The median of 65 and 90 is the same as their mean: 77.5The median of 65 and 90 is the same as their mean: 77.5The median of 65 and 90 is the same as their mean: 77.5
mean = (65 + 56 + 57 + 75 + 76 + 66 + 64)/7 = 65.57 median = "middle" number = 65 mode = most common number = all are equally common
Median is 70 The median is the middle number once you have reordered the sequence (therefore, 72 is not the median). The mode is the most common number The mean is the average.
Median = middle number = mean of 65 & 66 which is 65.5.
One possible data set is {100, 100, 100, 20, 30, 40}, where the mode is 100 (as it appears most frequently), the mean is 100 (sum is 390, divided by 6 gives 65), and the median is 100 (the average of the third and fourth values, which are both 100). Another data set could be {100, 100, 100, 10, 20, 30}, also with a mode of 100, a mean of 65 (sum is 360), and a median of 100. In both cases, the mean is less than the median.
Median of the set = arithmetic mean of 75 and 85 = 80
64 64 64 65 65 65 65 67 67 68 68 70 70 72 73 76 79 80. NB Place the numbers in RANK order. In this case it is already done #1 MODE ; is the term that occurs most frequently. In this case it is '65' , as there are four lots of '65' #2 MEDIAN ; is the term that occurs at the ABSOLUTE middle of the ranked order. Since there are eighteen terms, there is no absolute middle term. So we take the two middle terms that have the same number of terms to their side, that is terms nine & ten. They are 67 & 68. We then add these two together and halve the result. Hence (67 + 68) / 2 = 67.5. This is the median term. #3 MEAN ; is the sum of all the terms, which is the divided by the number of terms. Hence (64+64+64+65+65+65+65+67+67+68+68+70+70+72+73+76+79+80)/18 = 69' NB Another way of calculating the mean is ((3x64)+(4x65)+(2x67)+(2x68)+(2x70)+72+73+76+79+80)/18 = 69 NNB The word 'average' is casually used in the non-mathematical world, but the correct term is MEAN.
The mean will go from 5 to 15.833...The median will go from 7 to 7.5The mean will go from 5 to 15.833...The median will go from 7 to 7.5The mean will go from 5 to 15.833...The median will go from 7 to 7.5The mean will go from 5 to 15.833...The median will go from 7 to 7.5
step 1. arrange the numbers in ascending order (from low to high) as follows. was: 64 80 64 70 76 79 67 72 65 73 68 65 67 65 70 62 67 68 65 64 now: 62 64 64 64 65 65 65 65 67 67 67 68 68 70 70 72 73 76 79 80 step 2. count the number of the numbers above, or assign an index as follows. string: 62 64 64 64 65 65 65 65 67 67 67 68 68 70 70 72 73 76 79 80 index: 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 so the count is 20. The mode is the number most frequently observed. The mode is 65, which occurs four times. The median is the number in the middle. In this case, the 10th and 11th numbers both qualify for consideration. We take the average of the two numbers. The median is therefore 67. Alternate methods: 1) Use Microsoft Excel statistical functions of =mode() and =median() 2) Draw a bar graph with the horizontal axis of integers from 62 to 80. The y-axis is the frequency observed for that specific x value. For example, the frequency for 62 is one. The frequency for 63 is zero, and so on. The mode is the bar with the highest count. The median is not so obvious from a bar graph, unless the distribution is symmetric. Need some manual counting.