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What would you choose mean median mode or range for the numbers 56 78 85 92 65 79 15?
Mean: 67.143 Median: 78 Mode: 56, 78, 85, 92, 65, 79, 15 Range: 77
Find the range median and mode for 57 61 58 54 68 51 65 and 75?
Range: 24 Median: 59.5 Mode: 57, 61, 58, 54, 68, 51, 65, 75
What is the median of 65 and 90?
The median of 65 and 90 is the same as their mean: 77.5The median of 65 and 90 is the same as their mean: 77.5The median of 65 and 90 is the same as their mean: 77.5The median of 65 and 90 is the same as their mean: 77.5
What is the median in 70 68 72 65 70?
Median is 70 The median is the middle number once you have reordered the sequence (therefore, 72 is not the median). The mode is the most common number The mean is the average.
What can be two different data sets with 6 numbers. But the mode is 100 and the mean is less then the median?
One possible data set is {100, 100, 100, 20, 30, 40}, where the mode is 100 (as it appears most frequently), the mean is 100 (sum is 390, divided by 6 gives 65), and the median is 100 (the average of the third and fourth values, which are both 100). Another data set could be {100, 100, 100, 10, 20, 30}, also with a mode of 100, a mean of 65 (sum is 360), and a median of 100. In both cases, the mean is less than the median.
What is the mean median mode and range of 65 56 57 75 76 66 64?
65,56,57,75,76 ,68,64. First of all rearrange the terms in RANK order. Hence 56,57,64,65,66,75,76. MEDIAN. Select the absolute middle term from the rank order, which is 65. 65 is the Median. NB There are three terms to either side of this number. MODE. Select the term that occurs most frequently. Since all the terms occur only once, then you select the middle term, which is 65 again. MEAN. You add all the terms and then divide by the number of terms. Hence [56+57+64+65+66+75+76] / 7 => 459/7 => 65.57142857... ~ 65.57 ( 2 d.p.) ( The Mean) RANGE . is the difference between the highest value and the lowest value. Hence 76 - 56 = 20 ( The range)
What would you choose mean median mode or range for the numbers 56 78 85 92 65 79 15?
Mean: 67.143 Median: 78 Mode: 56, 78, 85, 92, 65, 79, 15 Range: 77
Find the range median and mode for 57 61 58 54 68 51 65 and 75?
Range: 24 Median: 59.5 Mode: 57, 61, 58, 54, 68, 51, 65, 75
Find the mean median and mode 65 56 57 75 76 66 64?
mean = (65 + 56 + 57 + 75 + 76 + 66 + 64)/7 = 65.57 median = "middle" number = 65 mode = most common number = all are equally common
What is the median of 65 and 90?
The median of 65 and 90 is the same as their mean: 77.5The median of 65 and 90 is the same as their mean: 77.5The median of 65 and 90 is the same as their mean: 77.5The median of 65 and 90 is the same as their mean: 77.5
What is the median in 70 68 72 65 70?
Median is 70 The median is the middle number once you have reordered the sequence (therefore, 72 is not the median). The mode is the most common number The mean is the average.
What can be two different data sets with 6 numbers. But the mode is 100 and the mean is less then the median?
One possible data set is {100, 100, 100, 20, 30, 40}, where the mode is 100 (as it appears most frequently), the mean is 100 (sum is 390, divided by 6 gives 65), and the median is 100 (the average of the third and fourth values, which are both 100). Another data set could be {100, 100, 100, 10, 20, 30}, also with a mode of 100, a mean of 65 (sum is 360), and a median of 100. In both cases, the mean is less than the median.
What is the median of 63 65 66 and 75?
Rearrange the terms into their rank order. Already done!!! 63,65,66,75 For an EVEN number of terms; there are four terms here, and four is an even number. You take the middle two terms, which are ,65, & 66. and find the mid-point between them, Which is 65.5 Hence ' 65.5 ' is the MEDIAN term. NB If you have an ODD number of terms, 5 in this case, e,g, 63,65,66,66,75. Then you select the absolute middle term, which is ' 66 '.
What is the median of 60 95 100 75 65 85 90 70?
Median of the set = arithmetic mean of 75 and 85 = 80
What is the mean mode median of 64 64 64 65 65 65 65 67 67 68 68 70 70 72 73 76 79 80?
64 64 64 65 65 65 65 67 67 68 68 70 70 72 73 76 79 80. NB Place the numbers in RANK order. In this case it is already done #1 MODE ; is the term that occurs most frequently. In this case it is '65' , as there are four lots of '65' #2 MEDIAN ; is the term that occurs at the ABSOLUTE middle of the ranked order. Since there are eighteen terms, there is no absolute middle term. So we take the two middle terms that have the same number of terms to their side, that is terms nine & ten. They are 67 & 68. We then add these two together and halve the result. Hence (67 + 68) / 2 = 67.5. This is the median term. #3 MEAN ; is the sum of all the terms, which is the divided by the number of terms. Hence (64+64+64+65+65+65+65+67+67+68+68+70+70+72+73+76+79+80)/18 = 69' NB Another way of calculating the mean is ((3x64)+(4x65)+(2x67)+(2x68)+(2x70)+72+73+76+79+80)/18 = 69 NNB The word 'average' is casually used in the non-mathematical world, but the correct term is MEAN.
How will adding the value 65 affect the mean and median of the data set 3 3 7 8 9?
The mean will go from 5 to 15.833...The median will go from 7 to 7.5The mean will go from 5 to 15.833...The median will go from 7 to 7.5The mean will go from 5 to 15.833...The median will go from 7 to 7.5The mean will go from 5 to 15.833...The median will go from 7 to 7.5
What is the mean mode and median of this data 64 80 64 70 76 79 67 72 65 73 68 65 67 65 70 62 67 68 65 64?
step 1. arrange the numbers in ascending order (from low to high) as follows. was: 64 80 64 70 76 79 67 72 65 73 68 65 67 65 70 62 67 68 65 64 now: 62 64 64 64 65 65 65 65 67 67 67 68 68 70 70 72 73 76 79 80 step 2. count the number of the numbers above, or assign an index as follows. string: 62 64 64 64 65 65 65 65 67 67 67 68 68 70 70 72 73 76 79 80 index: 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 so the count is 20. The mode is the number most frequently observed. The mode is 65, which occurs four times. The median is the number in the middle. In this case, the 10th and 11th numbers both qualify for consideration. We take the average of the two numbers. The median is therefore 67. Alternate methods: 1) Use Microsoft Excel statistical functions of =mode() and =median() 2) Draw a bar graph with the horizontal axis of integers from 62 to 80. The y-axis is the frequency observed for that specific x value. For example, the frequency for 62 is one. The frequency for 63 is zero, and so on. The mode is the bar with the highest count. The median is not so obvious from a bar graph, unless the distribution is symmetric. Need some manual counting.
