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The mode, median, and range of a single data point such as 65 are all the data point itself, 65 in this instance.

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Q: What is the mode median mean and range of 65?
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What is the mean median mode and range of 65 56 57 75 76 66 64?

56, 57, 64, 65, 66, 75, 76 Mean: 65 and 4/7 Median: 65 Mode: There is no mode. Range: 20


What would you choose mean median mode or range for the numbers 56 78 85 92 65 79 15?

Mean: 67.143 Median: 78 Mode: 56, 78, 85, 92, 65, 79, 15 Range: 77


Find the range median and mode for 57 61 58 54 68 51 65 and 75?

Range: 24 Median: 59.5 Mode: 57, 61, 58, 54, 68, 51, 65, 75


Find the mean median and mode 65 56 57 75 76 66 64?

mean = (65 + 56 + 57 + 75 + 76 + 66 + 64)/7 = 65.57 median = "middle" number = 65 mode = most common number = all are equally common


What is the median of 65 and 90?

The median of 65 and 90 is the same as their mean: 77.5The median of 65 and 90 is the same as their mean: 77.5The median of 65 and 90 is the same as their mean: 77.5The median of 65 and 90 is the same as their mean: 77.5


What is the median in 70 68 72 65 70?

Median is 70 The median is the middle number once you have reordered the sequence (therefore, 72 is not the median). The mode is the most common number The mean is the average.


What is the median of 63 65 66 and 75?

Median = middle number = mean of 65 & 66 which is 65.5.


What is the median of 60 95 100 75 65 85 90 70?

Median of the set = arithmetic mean of 75 and 85 = 80


What is the mean mode median of 64 64 64 65 65 65 65 67 67 68 68 70 70 72 73 76 79 80?

64 64 64 65 65 65 65 67 67 68 68 70 70 72 73 76 79 80. NB Place the numbers in RANK order. In this case it is already done #1 MODE ; is the term that occurs most frequently. In this case it is '65' , as there are four lots of '65' #2 MEDIAN ; is the term that occurs at the ABSOLUTE middle of the ranked order. Since there are eighteen terms, there is no absolute middle term. So we take the two middle terms that have the same number of terms to their side, that is terms nine & ten. They are 67 & 68. We then add these two together and halve the result. Hence (67 + 68) / 2 = 67.5. This is the median term. #3 MEAN ; is the sum of all the terms, which is the divided by the number of terms. Hence (64+64+64+65+65+65+65+67+67+68+68+70+70+72+73+76+79+80)/18 = 69' NB Another way of calculating the mean is ((3x64)+(4x65)+(2x67)+(2x68)+(2x70)+72+73+76+79+80)/18 = 69 NNB The word 'average' is casually used in the non-mathematical world, but the correct term is MEAN.


How will adding the value 65 affect the mean and median of the data set 3 3 7 8 9?

The mean will go from 5 to 15.833...The median will go from 7 to 7.5The mean will go from 5 to 15.833...The median will go from 7 to 7.5The mean will go from 5 to 15.833...The median will go from 7 to 7.5The mean will go from 5 to 15.833...The median will go from 7 to 7.5


Why is median age good?

65


What is the mean mode and median of this data 64 80 64 70 76 79 67 72 65 73 68 65 67 65 70 62 67 68 65 64?

step 1. arrange the numbers in ascending order (from low to high) as follows. was: 64 80 64 70 76 79 67 72 65 73 68 65 67 65 70 62 67 68 65 64 now: 62 64 64 64 65 65 65 65 67 67 67 68 68 70 70 72 73 76 79 80 step 2. count the number of the numbers above, or assign an index as follows. string: 62 64 64 64 65 65 65 65 67 67 67 68 68 70 70 72 73 76 79 80 index: 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 so the count is 20. The mode is the number most frequently observed. The mode is 65, which occurs four times. The median is the number in the middle. In this case, the 10th and 11th numbers both qualify for consideration. We take the average of the two numbers. The median is therefore 67. Alternate methods: 1) Use Microsoft Excel statistical functions of =mode() and =median() 2) Draw a bar graph with the horizontal axis of integers from 62 to 80. The y-axis is the frequency observed for that specific x value. For example, the frequency for 62 is one. The frequency for 63 is zero, and so on. The mode is the bar with the highest count. The median is not so obvious from a bar graph, unless the distribution is symmetric. Need some manual counting.