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There is no value of x that satisfies the equation. You may be missing an operator (+. - sign).
x = -8 and x = 4.x2 + 4x - 32 = 0We can factor this to:(x + 8) (x - 4) = 0Therefore:x + 8 = 0x = -8andx - 4 = 0x = 4Thus the two roots of the quadratic equation are -8 & 4.
An equation must have 1, 0, or infinitely many solutions. So if you find 1 and there is another, you have know it has infinitely many. For example. 0x+2=2 I solve this and the equations become 0x=0 Now, 1 is a solutions, but so is 2. I now know there are infinitely many. How about 0x+2=3. No solution and 2x+2=4, has one solution. I put those two here so you might try other numbers and see that they have no solutions and one solution. A special type of equation known as an identity is an equation that holds for all numbers. This means it has infinitely many solutions.
-28
Multiply all terms in the second equation by 5: 11x+10y = 147 0x+10y = 70 Subtract the second equation from the first equation in order to eliminate y: 11x = 77 Divde both sides by 11 in order to find the value of x: x = 7 Substitute the value of x into the original equations to find the value of y: Therefore it follows that x = 7 and y = 7