It might refer to 3 molecules of H2 (diatomic hydrogen).
V1 = (1/3)(pi)(r12)(h1) V2 = (1/3)(pi)(xr12)(h2) V1 = V2 , which means that: (1/3)(pi)(r12)(h1) = (1/3)(pi)(xr12)(h2) Divide both sides by (1/3)(pi) and you get: (r12)(h1) = (xr12)(h2) -> (r12)(h1) = x2(r12)(h2) Divide both sides by (r12) and you get: h1 = x2(h2) -> h2 = (h1)/x2 For example: Cone1: r1 = 10, h1 = 10 Cone2: r2 = 30, h2 = (10/32) = 10/9 = 1.11111111 Then to check: Volume of a cone = (1/3)(pi)(r2)(h) V1 = (1/3)(pi)(102)(10) V1 = 1047.197551 = V2 1047.197551 = (1/3)(pi)(302)(h2) h2 = 1047.197551/((900pi)/3) h2 = 1.111111111 = 10/9
H2 +o2=h2ogive suggestion about this formulateklahaymanot tsegay
It is an expression and a term that are of equal value
-98
H2 - hydrogen.
(N2) + 3(H2) = 2(NH3)
Hydrogen peroxide
V1 = (1/3)(pi)(r12)(h1) V2 = (1/3)(pi)(xr12)(h2) V1 = V2 , which means that: (1/3)(pi)(r12)(h1) = (1/3)(pi)(xr12)(h2) Divide both sides by (1/3)(pi) and you get: (r12)(h1) = (xr12)(h2) -> (r12)(h1) = x2(r12)(h2) Divide both sides by (r12) and you get: h1 = x2(h2) -> h2 = (h1)/x2 For example: Cone1: r1 = 10, h1 = 10 Cone2: r2 = 30, h2 = (10/32) = 10/9 = 1.11111111 Then to check: Volume of a cone = (1/3)(pi)(r2)(h) V1 = (1/3)(pi)(102)(10) V1 = 1047.197551 = V2 1047.197551 = (1/3)(pi)(302)(h2) h2 = 1047.197551/((900pi)/3) h2 = 1.111111111 = 10/9
Hydrogen peroxide
To solve this problem, we need to use the balanced chemical equation for the reaction between H2 and NH3. Given that the molar ratio between H2 and NH3 is 3:2, we can set up a proportion to find the number of moles of H2 needed. Using the formula: Moles of H2 = 12.36 moles NH3 * (3 moles H2 / 2 moles NH3) = 18.54 moles H2.
ya . H2 SO4 is an salt .(strong electrolite) because it is a salt (i=3).
There are approximately 1340 molecules of hydrogen in 10 grams of hydrogen.
Balanced equation. N2 + 3H2 --> 2NH3 1.4 moles H2 (2 moles NH3/3 moles H2) = 0.93 moles NH3 produced =======================
it means how many carbons there are
H2 represents a molecule of hydrogen gas, which consists of two hydrogen atoms bonded together. Its chemical formula is simply H2.
The reaction between nitrogen and hydrogen to form ammonia is: N2 + 3 H2 → 2 NH3 The above is the reaction for the Haber process in the industrial synthesis of ammonia. For a given proportion of 3 N2 to 2 H2 (or in ratio terms equivalent to 4.5 N2 to 3 H2), we see that H2 is the limiting reactant. Thus according to the stoichiometry of the reaction, 2 moles of H2 will form 1.33 moles of NH3.
Three: The reaction equation is N2 + 3 H2 -> 2 NH3