Q: What do you need to get in IB?

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as a2+b2=(a+ib)(a-ib), b2+2=[b - i sqrt(2)] [b + i sqrt(2)]

It already is in the form a+ib. a = root 7, the b=1 (i.e 1 x i ).

No

If you have a complex function in the form "a+ib", the (complex) conjugate is "a-ib". "Conjugate" is usually a function that the original function must be multiplied by to achieve a real number.

Numbers of the form a + ib (where i = -11/2; a and b are real numbers) are called complex numbers.For any two complex numbers (a+ib) and (c+id):Addition:(a+ib) + (c+id) = (a+c) + i(b+d)So, -8i-7i = (-8-7)i = -15i

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you might need to search google for ib game on windows computer and press ib download game and you will be able to play the game for free or you can just see how people download ib and you can do it the same way the people do to download ib

No, you don't. While taking the IB program can be beneficial, depending on the area you wish to pursue, it isn't a requirement for admission.

Pre-IB is the material learned in the IB program in the 9th and 10th grade 11th and 12th grade is IB material

Need the name of the maker to answer.

On average you would need 75-85% depending on how hard the test is. This is because the IB only awards 7s to about 5% of all tested candidates.

no

Ib Dam's birth name is Ib Andreas Dam.

Ib Freuchen's birth name is Ib Frederik Freuchen.

IA and IB is dominant to ii or sometimes preferred IO.

ib. is that even a question

start at Ic'= Ic1+Ic2 Ib'=Ib1 Ic1=B1*Ib' Ie1=Ib2=Ib'(B1+1)=Ib'B1 + Ib' Ic' = Ib'*B1 + Ic2 Ic2= B2(Ib'B1+Ib') Ic' = Ib'B1 + Ib'B1B2 + Ib'B2 divide by Ib' Ic'/Ib'= current gain =B'=B1+B2+B1B2 note: calculations without resistance

Ib Glindemann's birth name is Glindemann Nielsen, Ib Niels Carl.