10 mL of nitric acid has a mass of 15.1 grams.
Nitric acid = HNO3
when sodium thiosulphate is mix with nitric acid what is form
salt+heat
0.2 milligrams.
density = mass/volume density = grams/ cubic centimeter 1 cubic centimeter = 1 milliliter density = 17.84/15 = 1.19 grams/milliliter
The molar mass of nitric acid (HNO3) is approximately 63 grams per mole.
The molar mass of nitric acid (HNO3) is 63.01 g/mol. To find the total grams in 4 moles, you would multiply the molar mass by the number of moles: 63.01 g/mol x 4 mol = 252.04 grams. So, there would be 252.04 grams in four moles of nitric acid (HNO3).
Copper reacts with nitric acid to form copper nitrate, nitrogen dioxide gas, and water. The reaction is a redox reaction where copper is oxidized and nitric acid is reduced. Be cautious when handling nitric acid as it is a strong acid and can be corrosive.
To calculate the weight of nitric acid produced from 18.5 grams of nitrogen dioxide, you need to consider the stoichiometry of the reaction. The balanced chemical equation is: 2NO2 + H2O -> HNO3 + NO From the equation, we see that 2 moles of nitrogen dioxide produce 1 mole of nitric acid. First, convert 18.5 grams of nitrogen dioxide to moles, then use the mole ratio to find the moles of nitric acid produced. Finally, convert the moles of nitric acid to grams using the molar mass of nitric acid.
1+7+(8x3) =32 =32x2 (2 moles) =64
To determine the maximum mass of nitric acid required to react with 0.35 grams of copper metal, we need to calculate the moles of copper using its molar mass. Then, we use the balanced chemical equation between copper and nitric acid to find the mole ratio between them. Finally, we convert the moles of copper to moles of nitric acid and then to grams. The maximum mass of nitric acid needed can be determined as per the stoichiometry of the balanced chemical equation.
Nitiric acid
98g
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Nitric acid is not a very strong acid. Adding distilled water will cause it to be more diluted. Its acidity does not change. However, to neutralize it, you do not need more alkali as compared to before adding the distilled water.
No, it does not
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