Q: What does 3 BGG mean?

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uhjjh idkyutghjk gkujkfjgnhuyjyijgh yjr ufyhfjhmn hngfghb bgg hgnb hgghnb tygnb e4gb 34refgvb

33% for every girl... (quick but wrong)2. for a given solo pregnancy, we have the b-g option, or 1/2.For two pregnancies, we have bb, bg, gb, gg.for three pregnancies, we have bbb, bbg, bgb, bgg, ggg, gbg, ggb, gbb.Of which some outcomes are equivalent in terms of numbers. (e.g. ggb, gbg, bgg)However only one of the eight outcomes gives three girls, so the answer is the probablilty is 1/8.An easier method, and necessary when the number are greater, is to say the probability is 1/2 in one pregnancy.And since (for our purposes) the pregnancies are independent events, the cumulative probability is (1/2)3 which = 1/8 or 12.5% or 0.125.

The 8 possible outcomes for three children are: * ggg * ggb * gbg * gbb * bgg * bgb * bbg * bbb Of these, two girls and a boy occurs 3 out of 8 times, which is a probability of 0.375. This assumes that the probability of a boy and girl being in the family is equal, which is not entirely true for a large number of reasons.

3-50hz mean = -47

5.1 is the mean of 7.2 and 3.

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We can write the sample space for 3 children as follows (b=boy, g=girl). bbb gbb bbg gbg bgb ggg bgg ggb The sample space is 8; each has a probability of 1/8. From above, you can see 3 instances that have 1 boy; bgg, gbg & ggb. Therefore, add 1/8 + 1/8 + 1/8 = 3/8 probability one boy having three children.

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uhjjh idkyutghjk gkujkfjgnhuyjyijgh yjr ufyhfjhmn hngfghb bgg hgnb hgghnb tygnb e4gb 34refgvb

33% for every girl... (quick but wrong)2. for a given solo pregnancy, we have the b-g option, or 1/2.For two pregnancies, we have bb, bg, gb, gg.for three pregnancies, we have bbb, bbg, bgb, bgg, ggg, gbg, ggb, gbb.Of which some outcomes are equivalent in terms of numbers. (e.g. ggb, gbg, bgg)However only one of the eight outcomes gives three girls, so the answer is the probablilty is 1/8.An easier method, and necessary when the number are greater, is to say the probability is 1/2 in one pregnancy.And since (for our purposes) the pregnancies are independent events, the cumulative probability is (1/2)3 which = 1/8 or 12.5% or 0.125.

The 8 possible outcomes for three children are: * ggg * ggb * gbg * gbb * bgg * bgb * bbg * bbb Of these, two girls and a boy occurs 3 out of 8 times, which is a probability of 0.375. This assumes that the probability of a boy and girl being in the family is equal, which is not entirely true for a large number of reasons.

Mean is the average of numbers. 1 + 3 + 5 = 9 / 3 = 3 (So 3 is the mean number).

3-50hz mean = -47