33% for every girl... (quick but wrong)
2. for a given solo pregnancy, we have the b-g option, or 1/2.
For two pregnancies, we have bb, bg, gb, gg.
for three pregnancies, we have bbb, bbg, bgb, bgg, ggg, gbg, ggb, gbb.
Of which some outcomes are equivalent in terms of numbers. (e.g. ggb, gbg, bgg)
However only one of the eight outcomes gives three girls, so the answer is the probablilty is 1/8.
An easier method, and necessary when the number are greater, is to say the probability is 1/2 in one pregnancy.
And since (for our purposes) the pregnancies are independent events, the cumulative probability is (1/2)3 which = 1/8 or 12.5% or 0.125.
3 out of 7
1/32
you have a 75% chance
It depends on the couples' genes. Also, at present the probability of a girls is approx 0.48
The probability of a boy is still 0.5 no matter how many prior children there are.
Assuming that the probability of having a baby girl is 1/2 and that of having a baby boy is 1/2, the probability of having 3 baby girls in a row is (1/2)(1/2)(1/2)=1/8.
50%
3 out of 7
1/32
There is no simple answer to the question because the children's genders are not independent events. They depend on the parents' ages and their genes. However, if you assume that they are independent events then, given that the probability of a boy is approx 0.52, the probability of 3 girls out of 4 children is 0.2331
you have a 75% chance
It depends on the couples' genes. Also, at present the probability of a girls is approx 0.48
The probability of a boy is still 0.5 no matter how many prior children there are.
Assuming that having boys and girls are equally likely, then the probability is 1/8. * * * * * You also need to assume that the children's genders are independent. They are NOT and depend on the parents' ages and genes.
It is 3/8.
1/35
The probability of exactly 3 girls in a family of 10 children, assuming equal chance of a boy or girl, is 0.1172. This is a binomial distribution.