The expression (3x \cdot 2y) represents the multiplication of the two terms. When multiplied together, it equals (6xy). This is obtained by multiplying the coefficients (3 and 2) to get 6, and then combining the variables (x) and (y).
5
An algebraic equation with an infinite number of solutions
-3x + 2y = 12-3x + 3x + 2y = 3x + 122y = 3x + 122y/2 = 3x/2 + 12/2y = (3/2)x + 6
-3x + 2y = -4There are lots of different ways to write it.Here are a few:-3x = -2y - 43x = 2y + 42y = 3x - 4-2y = -3x + 4x = 2y/3 + 4/3y = 3x/2 - 2
3x-2y=6 -2y=-3x+6 y=1.5x-3
wat does 2y-3x-6 equal
5
3x+2y-7=0 2y=-3x+7 y=1/2(-3x+7) or -3/2 x +7/2
3x = 2y + 3 3x -3 = 2y +3 -3 3x - 3 = 2y (3x -3)/2 = 2y / 2 y = 1/2 x (3x - 3) 3x = 2y +3 3x - 3x = -3x +2y +3 0 = -3x +2y +3 -1 x (0) = -1 x (-3x +2y +3) 0 = 3x - 2y -3
3x = 2y + 3 3x -3 = 2y +3 -3 3x - 3 = 2y (3x -3)/2 = 2y / 2 y = 1/2 x (3x - 3) 3x = 2y +3 3x - 3x = -3x +2y +3 0 = -3x +2y +3 -1 x (0) = -1 x (-3x +2y +3) 0 = 3x - 2y -3
(3x-2y)2=
(14x-2y)+(7x-3y)+(-3x) = 14x-2y+7x-3y-3x =(14+7-3)x-(2+3)y =18x-5y
An algebraic equation with an infinite number of solutions
(3x-2y)2=
We need to get both equations into slope-intercept form. If they are parallel, they will have the same slope. If they are perpendicular, they will have slopes that when multiplied equal -1. (unless one line is horizontal and the other vertical) 3x+2y=5 2y=5-3x y=(-3/2)x+(5/2) 3x+2y=9 2y=9-3x y=(-3/2)x+(9/2) The two lines are parallel, since both slopes are equal to (-3/2).
-3x + 2y = 9 2y = 3x + 9y = 1,5x + 4,5
4x-2y+3x+2y When simplified: 7x