y = x²-6x+5 is the equation.
If it is factorized, you get (x-5)(x-1)
We need y to equal zero, so either (x-5) or (x-1) can be zero (because 0 times anything equals 0).
So, x-5 = 0 meaning that x=5
or
x-1 = 0 meaning that x=1
Hope this helps!
The equation that has the solutions ( x = 1 \pm \sqrt{5} ) can be derived from the quadratic formula. Specifically, these solutions can be expressed as roots of the equation ( x^2 - 2x - 4 = 0 ). When simplified, this equation matches the given solutions, as substituting ( x = 1 \pm \sqrt{5} ) satisfies the equation.
x2 - 12x + 35
The discriminant is 36 which means the quadratic equation has two solutions which are 5 and -1
(x + 5) (x + 1) = 0x2 + 6x + 5 = 0
x2 - 8x + 15
The given expression is a quadratic equation. To find its solutions, we can either factor the equation or use the quadratic formula. However, without an equation to solve or any context, it is not possible to provide a numeric answer.
The equation must have roots of x = -1 and x = 5 So: x + 1 = 0 and x - 5 = 0 Therefore: (x + 1)(x - 5) = 0 Expanding the brackets gives the equation: x2 - 4x - 5 = 0
This is a quadratic equation which will have two solutions: X2 = 4x+5 Rearrange the equation: x2-4x-5 = 0 Factor the equation: (x+1)(x-5) = 0 So the solutions are: x = -1 or x = 5
There are no real solutions because the discriminant of the quadratic equation is less than zero.
The number of solutions an equation has depends on the nature of the equation. A linear equation typically has one solution, a quadratic equation can have two solutions, and a cubic equation can have three solutions. However, equations can also have no solution or an infinite number of solutions depending on the specific values and relationships within the equation. It is important to analyze the equation and its characteristics to determine the number of solutions accurately.
x2 + 4x = 41
It is a quadratic equation in the form of y2-4y-5 = 0 and will have two solutions: When factorised: (y-5)(y+1) = 0 Therefore: y = 5 or y = -1