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Which equation has the solutions x equals 1 plus and minus the square root of 5?
The equation that has the solutions ( x = 1 \pm \sqrt{5} ) can be derived from the quadratic formula. Specifically, these solutions can be expressed as roots of the equation ( x^2 - 2x - 4 = 0 ). When simplified, this equation matches the given solutions, as substituting ( x = 1 \pm \sqrt{5} ) satisfies the equation.
What quadratic equation has solutions of 5 and 7?
x2 - 12x + 35
What is the discriminant for x2-4x-5 equals 0?
The discriminant is 36 which means the quadratic equation has two solutions which are 5 and -1
Write a quadratic equation having the given numbers as solutions negative 5 and negative 1?
(x + 5) (x + 1) = 0x2 + 6x + 5 = 0
2x square plus 11x plus 5 equals?
The given expression is a quadratic equation. To find its solutions, we can either factor the equation or use the quadratic formula. However, without an equation to solve or any context, it is not possible to provide a numeric answer.
What is the quadratic equation with the solutions -1 an 5?
The equation must have roots of x = -1 and x = 5 So: x + 1 = 0 and x - 5 = 0 Therefore: (x + 1)(x - 5) = 0 Expanding the brackets gives the equation: x2 - 4x - 5 = 0
Find the quadratic equation if the following solutions are 3 and 5?
x2 - 8x + 15
The Square of a number is 5 more than 4 times the number. Find the number that makes the sentence true.?
This is a quadratic equation which will have two solutions: X2 = 4x+5 Rearrange the equation: x2-4x-5 = 0 Factor the equation: (x+1)(x-5) = 0 So the solutions are: x = -1 or x = 5
How many real solutions are there for the equation x2 plus 3x plus 5 equals 0?
There are no real solutions because the discriminant of the quadratic equation is less than zero.
Choose the quadratic equation with a leading coefficient of 1 that has as solutions -2 plus 3 square root 5 and -2 -3 square root 5?
x2 + 4x = 41
What is y squared minus 4y minus 5?
It is a quadratic equation in the form of y2-4y-5 = 0 and will have two solutions: When factorised: (y-5)(y+1) = 0 Therefore: y = 5 or y = -1
How do you translate Quadratic equation?
Translate to what? I assume you need help interpreting it. The quadratic equation is used to solve the quadratic polynomial, ax2 + bx + c = 0, where a, b, and c can be any number. For example, if you need to solve the equation x2 = 5 + 2x, you first convert it into the standard form mentioned above: x2 - 2x - 5 = 0. Now find the coefficients, a, b, and c. In this case, a = 1, b = -2, c = -5. Finally, you replace these coefficients in the quadratic equation. The "plus-minus" sign simply means that the quadratic equation is a shortcut for two equations - one in which you add, the other in which you subtract, the terms at the top. The solutions given by the quadratic equation are values of "x" that satisfy the equation.
