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How do you find the mass when given speed and kinetic energy?
You solve the equation for kinetic energy for mass. KE = (1/2) m v2 (1/2) m v2 = KE m = 2 KE / v2
How do you show mathematically why a small increase in your vehicle's speed results in a tremendous increase in your vehicles kinetic energy?
The kinetic energy of a vehicle, of mass m kilograms and travelling at velocity v metres per second, is 1/2*m*v2.Using calculus, d(ke)/dv = m*v.That is, the kinetic energy (ke) increases by the product of the mass and the velocity. Whether or not that can be considered "tremendous" is another matter.The kinetic energy of a vehicle, of mass m kilograms and travelling at velocity v metres per second, is 1/2*m*v2.Using calculus, d(ke)/dv = m*v.That is, the kinetic energy (ke) increases by the product of the mass and the velocity. Whether or not that can be considered "tremendous" is another matter.The kinetic energy of a vehicle, of mass m kilograms and travelling at velocity v metres per second, is 1/2*m*v2.Using calculus, d(ke)/dv = m*v.That is, the kinetic energy (ke) increases by the product of the mass and the velocity. Whether or not that can be considered "tremendous" is another matter.The kinetic energy of a vehicle, of mass m kilograms and travelling at velocity v metres per second, is 1/2*m*v2.Using calculus, d(ke)/dv = m*v.That is, the kinetic energy (ke) increases by the product of the mass and the velocity. Whether or not that can be considered "tremendous" is another matter.
How much work must be done on a 10 kilograms bicycle to increase its speed from 2 meters per second to 3 meters pe second?
When the bike is moving at 2 m/s, its kinetic energy is (1/2 m v2) = (5 x 4) = 20 joules.When it's moving at 3 m/s, its kinetic energy is (1/2 m v2) = (5 x 9) = 45 joules.The difference between initial KE and final KE is (45 - 20) = 25 joules.That's how much work you have to do on it in order to increase its KE.
How much work must be done on a 24 kg shopping cart to increase its speed from 1 m s to 4 m s?
Kinetic energy of a moving mass is [ 1/2 m V2 .Initial KE of the kart = (1/2) (24) (1)2 = 12 joules.Final KE = (1/2) (24) (4)2 = 192 joules.Difference = amount of energy due to increased speed = (192 - 12) =180 joules.
What are the two values of kinetic energy?
That can't be answered without the question but kinetic energy (KE) can be calculated like this: KE = 0.5mv2, where m is mass (kg) and v is velocity (m/s)
How do you find the mass when given speed and kinetic energy?
You solve the equation for kinetic energy for mass. KE = (1/2) m v2 (1/2) m v2 = KE m = 2 KE / v2
What are the kinematic equation of archery?
ke=M * v2 / 450,240 ke=Kinetic Energy M = mass (weight of arrow in grains)v = velocity of arrow in f.p.s.
What is the equation used to express the kinetic energy of a moving body?
KE = (1/2) m v2 Where KE = kinetic energy, m = the mass, and v is the speed.
What type of effect does an objects speed have on its kinetic energy than a change in its mass?
KE = .5 m v2
What is the relationship pattern between kinetic energy mass and speed?
KE = 0.5 x m x v2, where m is mass in kg, and v is speed in m/s.
What is the kinetic energy of an odject that has a mass of 20 kilograms and a speed of 2.8?
Kinetic energy is given by 1/2 x M x V2. So if M = 20kg, and V= 2.8 meters/sec, V2 = 7.84, KE = 78.4 Joules.
How do you show mathematically why a small increase in your vehicle's speed results in a tremendous increase in your vehicles kinetic energy?
The kinetic energy of a vehicle, of mass m kilograms and travelling at velocity v metres per second, is 1/2*m*v2.Using calculus, d(ke)/dv = m*v.That is, the kinetic energy (ke) increases by the product of the mass and the velocity. Whether or not that can be considered "tremendous" is another matter.The kinetic energy of a vehicle, of mass m kilograms and travelling at velocity v metres per second, is 1/2*m*v2.Using calculus, d(ke)/dv = m*v.That is, the kinetic energy (ke) increases by the product of the mass and the velocity. Whether or not that can be considered "tremendous" is another matter.The kinetic energy of a vehicle, of mass m kilograms and travelling at velocity v metres per second, is 1/2*m*v2.Using calculus, d(ke)/dv = m*v.That is, the kinetic energy (ke) increases by the product of the mass and the velocity. Whether or not that can be considered "tremendous" is another matter.The kinetic energy of a vehicle, of mass m kilograms and travelling at velocity v metres per second, is 1/2*m*v2.Using calculus, d(ke)/dv = m*v.That is, the kinetic energy (ke) increases by the product of the mass and the velocity. Whether or not that can be considered "tremendous" is another matter.
Why is kinetic energy of an object four times larger when the speed doubles?
Kinetic energy is proportional to the square of velocity, so when the speed doubles, the kinetic energy increases by a factor of 2^2 = 4. This is because kinetic energy is given by the formula KE = 0.5 * m * v^2, where m is the mass of the object and v is its velocity.
How fast must a 2.0 kg basketball be thrown to start with a kinetic energy of 160 J?
The formula for kinetic energy is KE = 0.5 * m * v^2, where KE is kinetic energy, m is mass, and v is velocity. Rearranging the formula to solve for velocity, we get v = sqrt(2 * KE / m). Plugging in the values (KE = 160 J, m = 2.0 kg), we find that the basketball must be thrown with a velocity of approximately 8 m/s.
What is the formula a getting kenetic enegry?
The formula for calculating kinetic energy is KE = 0.5 * m * v^2, where KE is the kinetic energy, m is the mass of the object, and v is the velocity of the object.
What is the speed of a 0.149 kg baseball if its kinetic energy is 107j?
The kinetic energy of an object is given by the formula KE = 0.5 * m * v^2, where m is the mass and v is the velocity. Rearranging the formula to solve for velocity, we get v = sqrt(2 * KE / m). Plugging in the values (KE = 107 J, m = 0.149 kg), we find that the speed of the baseball is approximately 26.2 m/s.
What is the kinetic energy of an object that has a mass of 20 kilograms and a speed of 2.8 m per s?
KE = 1/2 M V2 = 1/2 (20) (2.8)2 = 78.4 joules
