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The kinetic energy of a vehicle, of mass m kilograms and travelling at velocity v metres per second, is 1/2*m*v2.

Using calculus, d(ke)/dv = m*v.

That is, the kinetic energy (ke) increases by the product of the mass and the velocity. Whether or not that can be considered "tremendous" is another matter.

The kinetic energy of a vehicle, of mass m kilograms and travelling at velocity v metres per second, is 1/2*m*v2.

Using calculus, d(ke)/dv = m*v.

That is, the kinetic energy (ke) increases by the product of the mass and the velocity. Whether or not that can be considered "tremendous" is another matter.

The kinetic energy of a vehicle, of mass m kilograms and travelling at velocity v metres per second, is 1/2*m*v2.

Using calculus, d(ke)/dv = m*v.

That is, the kinetic energy (ke) increases by the product of the mass and the velocity. Whether or not that can be considered "tremendous" is another matter.

The kinetic energy of a vehicle, of mass m kilograms and travelling at velocity v metres per second, is 1/2*m*v2.

Using calculus, d(ke)/dv = m*v.

That is, the kinetic energy (ke) increases by the product of the mass and the velocity. Whether or not that can be considered "tremendous" is another matter.

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