The sum of p and q means (p+q). The difference of p and q means (p-q).
This is a Hardy Weindburg situation P represents the percentage of the population that has a dominant allele... now there can only be two alleles one is dominant and one is recessive... q is the recessive allele This means that p+q=1 and so q has to be equal to 0.32 If you do the square of p (p^2) then that gives you the number of people who are homozygous dominant If you do the square of q (q^2) then that gives you the number of people who are homozygous recessive If you do 2*(p*q) then that will give you the number of people who are heterozygous Hope this helps...
1)p->q 2)not p or q 3)p 4)not p and p or q 5)contrudiction or q 6)q
p*q
if the statement is : if p then q converse: if q then p inverse: if not p then not q contrapositive: if not q then not
tan x
A+
A+
A+
Q
Q
formula: p2 + 2pq + q2 = 1 p+q=1 p = dominant (A) allele frequency q = recessive (a) allele frequency q2 = homozygous recessive frequency p2 = homozygous dominant frequency 2pq = heterozygous frequency
Converse: If p r then p q and q rContrapositive: If not p r then not (p q and q r) = If not p r then not p q or not q r Inverse: If not p q and q r then not p r = If not p q or not q r then not p r
The sum of p and q means (p+q). The difference of p and q means (p-q).
Not sure I can do a table here but: P True, Q True then P -> Q True P True, Q False then P -> Q False P False, Q True then P -> Q True P False, Q False then P -> Q True It is the same as not(P) OR Q
q + p
This is a Hardy Weindburg situation P represents the percentage of the population that has a dominant allele... now there can only be two alleles one is dominant and one is recessive... q is the recessive allele This means that p+q=1 and so q has to be equal to 0.32 If you do the square of p (p^2) then that gives you the number of people who are homozygous dominant If you do the square of q (q^2) then that gives you the number of people who are homozygous recessive If you do 2*(p*q) then that will give you the number of people who are heterozygous Hope this helps...