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There is no distributive property of addition over multiplication. The equation works if a + (b * c) = (a + b)*(a + c) = a2 + ab +ac +bc => a + bc = a2 + ab +ac +bc ie a = a2 + ab + ac = a*(a+b+c) and that, in turn requires that a = 0 or a+b+c = 1 If a, b and c are fractions than the second condition requires the fractions to sum to 1 - not be equal to 1.
2ca3ac = 6(ac)^2
5 - a - 1 + c - 6a2 + a2
A2 + B2 = C2 If C=8, then A2 + B2 = 64
a2-8a plus 12, if done correctly according to calculus, results in the number 2.