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Why does distributive property of addition over multiplication only works when the fractions are equal to 1?
There is no distributive property of addition over multiplication. The equation works if a + (b * c) = (a + b)*(a + c) = a2 + ab +ac +bc => a + bc = a2 + ab +ac +bc ie a = a2 + ab + ac = a*(a+b+c) and that, in turn requires that a = 0 or a+b+c = 1 If a, b and c are fractions than the second condition requires the fractions to sum to 1 - not be equal to 1.
What is 2 c a 3 a c?
2ca3ac = 6(ac)^2
How do you simplify 5-a-1 plus c-6a2 plus a2?
5 - a - 1 + c - 6a2 + a2
What are the lengths of and A plus B in a right triangle if C equals 8?
A2 + B2 = C2 If C=8, then A2 + B2 = 64
Solve for a a2-8a plus 12 a-2 -6b2 6 c -3 -4 d 3 4?
a2-8a plus 12, if done correctly according to calculus, results in the number 2.
What is the formula of a plus b plus c whole cube?
a3 + b3 + c3 + 2(a2)b + 2(b2)c + 2(a2)c + 2ab2 + 2(c2)b +abc
What are the formulas used in algebra?
(a+b)2a2+b2+2ab(a-b)2=a2+b2-2ab(a+b)2=(a-b)2+4ab(a-b)2=(a+b)2-4aba2-b2=(a+b)(a-b)(a+b+c)2=(a+b+c+2ab+2bc+2cz)(a+b)3=a3+b3+3ab(a+b)(a-b)3=a3-b3-3ab(a-b)a3+b3=(a-b)(a2-ab+b2)a3-b3=(a+b)(a2+ab+b2)a3+b3+c3-3abc=(a+b+c)(a2+b2+c2-ab-bc-ca)(x+a)(x+b)=x2+x(a+b)+ab ==3a+10b-b+2a=5a+9by=mx+b is another one
When copying the formula B3-C4A2 to the right the formula in column C would be?
First, there cannot be a cell called C4A2, so that can be assumed that you have left an operator out. So presuming your formula would be =B3-C4-A2, then when copying to the right, the column references will all change by one letter. B3 would become C3. C4 would become D4. A2 would become B2. So the formula =B3-C4-A2 would become =C3-D4-A2 when copied one cell to the right. The operators will not change, just the cell references.
Why does distributive property of addition over multiplication only works when the fractions are equal to 1?
There is no distributive property of addition over multiplication. The equation works if a + (b * c) = (a + b)*(a + c) = a2 + ab +ac +bc => a + bc = a2 + ab +ac +bc ie a = a2 + ab + ac = a*(a+b+c) and that, in turn requires that a = 0 or a+b+c = 1 If a, b and c are fractions than the second condition requires the fractions to sum to 1 - not be equal to 1.
What is the antonym for each word A connoisseur B nihilist C zenith from the choices given 1 bottom 2 beginner 3 believer?
A: novice, B: believer, C: bottom
What is a synonym A enigma B conjecture C mammoth D industry 1 large 2 puzzle 3 guess 4 activity?
A2, b3, c1, d4
What is 2 c a 3 a c?
2ca3ac = 6(ac)^2
How do you show that sum of 5 even number equals even number?
Any even number can be expressed as a multiple of two. If you have 5 even numbers, then we can label them as such: a1 = 2*b1 a2 = 2*b2 a3 = 2*b3 a4 = 2*b4 a5 = 2*b5 Where bn is an arbitrary integer So we therefore have: a1 + a2 + a3 + a4 + a5 = 2*b1 + 2*b2 +2*b3 + 2*b4 + 2*b5 = 2*(b1 + b2 +b3 + b4 + b5) We can then let b1 + b2 +b3 + b4 + b5 = c because our sum of 5 numbers is equal to 2*c, this means that the sum is a multiple of 2, and therefore even. QED.
How do you simplify 5-a-1 plus c-6a2 plus a2?
5 - a - 1 + c - 6a2 + a2
What does ac in AC-130 mean?
The A means attack or air to ground (A-10, A-6, etc) and the C means cargo (C-5, C-17). Since the AC-130 is a modified C-130, it carries both designators.
What is a2 b2?
c^2
Assuming A squared plus b squared equals c squared and a equals 6 and b equals 8 what is c?
A squared = 6x6 = 36 B squared = 8x8 = 64 Square root of 36+64 = 10 Given: a2 + b2 = c2 a = 6 and b = 8. We need to find the value of c. a = 6 implies a2 = 62 = (6*6) = 36. b = 8 implies b2 = 82 = (8*8) = 64. a2 + b2 = c2 implies 62 + 82 = c2 c2 = 36 + 64 c2 = 100 c2 = 102 c = 10
