Q: What does ac if a2 b3 and c 6?

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There is no distributive property of addition over multiplication. The equation works if a + (b * c) = (a + b)*(a + c) = a2 + ab +ac +bc => a + bc = a2 + ab +ac +bc ie a = a2 + ab + ac = a*(a+b+c) and that, in turn requires that a = 0 or a+b+c = 1 If a, b and c are fractions than the second condition requires the fractions to sum to 1 - not be equal to 1.

2ca3ac = 6(ac)^2

5 - a - 1 + c - 6a2 + a2

A2 + B2 = C2 If C=8, then A2 + B2 = 64

a2-8a plus 12, if done correctly according to calculus, results in the number 2.

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a3 + b3 + c3 + 2(a2)b + 2(b2)c + 2(a2)c + 2ab2 + 2(c2)b +abc

(a+b)2a2+b2+2ab(a-b)2=a2+b2-2ab(a+b)2=(a-b)2+4ab(a-b)2=(a+b)2-4aba2-b2=(a+b)(a-b)(a+b+c)2=(a+b+c+2ab+2bc+2cz)(a+b)3=a3+b3+3ab(a+b)(a-b)3=a3-b3-3ab(a-b)a3+b3=(a-b)(a2-ab+b2)a3-b3=(a+b)(a2+ab+b2)a3+b3+c3-3abc=(a+b+c)(a2+b2+c2-ab-bc-ca)(x+a)(x+b)=x2+x(a+b)+ab ==3a+10b-b+2a=5a+9by=mx+b is another one

First, there cannot be a cell called C4A2, so that can be assumed that you have left an operator out. So presuming your formula would be =B3-C4-A2, then when copying to the right, the column references will all change by one letter. B3 would become C3. C4 would become D4. A2 would become B2. So the formula =B3-C4-A2 would become =C3-D4-A2 when copied one cell to the right. The operators will not change, just the cell references.

There is no distributive property of addition over multiplication. The equation works if a + (b * c) = (a + b)*(a + c) = a2 + ab +ac +bc => a + bc = a2 + ab +ac +bc ie a = a2 + ab + ac = a*(a+b+c) and that, in turn requires that a = 0 or a+b+c = 1 If a, b and c are fractions than the second condition requires the fractions to sum to 1 - not be equal to 1.

A: novice, B: believer, C: bottom

A2, b3, c1, d4

2ca3ac = 6(ac)^2

Any even number can be expressed as a multiple of two. If you have 5 even numbers, then we can label them as such: a1 = 2*b1 a2 = 2*b2 a3 = 2*b3 a4 = 2*b4 a5 = 2*b5 Where bn is an arbitrary integer So we therefore have: a1 + a2 + a3 + a4 + a5 = 2*b1 + 2*b2 +2*b3 + 2*b4 + 2*b5 = 2*(b1 + b2 +b3 + b4 + b5) We can then let b1 + b2 +b3 + b4 + b5 = c because our sum of 5 numbers is equal to 2*c, this means that the sum is a multiple of 2, and therefore even. QED.

5 - a - 1 + c - 6a2 + a2

The A means attack or air to ground (A-10, A-6, etc) and the C means cargo (C-5, C-17). Since the AC-130 is a modified C-130, it carries both designators.

c^2

A squared = 6x6 = 36 B squared = 8x8 = 64 Square root of 36+64 = 10 Given: a2 + b2 = c2 a = 6 and b = 8. We need to find the value of c. a = 6 implies a2 = 62 = (6*6) = 36. b = 8 implies b2 = 82 = (8*8) = 64. a2 + b2 = c2 implies 62 + 82 = c2 c2 = 36 + 64 c2 = 100 c2 = 102 c = 10