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2ca3ac = 6(ac)^2
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Rewrite as, int[sinx 1/2 ] = - (2/3)cosx 3/2 + C ==================or = - (2/3)sqrt[cosx 3] + C ==================
a^2+b^2=c^2 3^2+4^2=c^2 9+16=c^2 25=c^2 (take square root of both sides) c=5