There is a 2 in 5 chance that the spinner will stop in a red section.
The depends on what other numbers exist on the spinner. If there are a total of six numbers on the spinner, for instance, the probability of spinning a 1-4 is 2 in 3.
To determine how many times you would expect to stop on a vowel when spinning a spinner 400 times, you first need to know the number of vowels on the spinner. Assuming the spinner has an equal chance of landing on each section and contains vowels, calculate the probability of landing on a vowel. Multiply that probability by 400 to get the expected number of times you would land on a vowel. For example, if there are 5 vowels out of 10 sections, the expectation would be 400 x (5/10) = 200 times.
It is (the number of sectors which are numbered 2) divided by 6
3 in 10.
well the question you wrote do not make any and please stop wasting your time on question like these be more specific you retard!
2/3
The depends on what other numbers exist on the spinner. If there are a total of six numbers on the spinner, for instance, the probability of spinning a 1-4 is 2 in 3.
17 out of 21
It depends on how many points there are that the spinner can land on. If there are 8, for example, the probability would be 8/16, or 1/2...
It depends on how many positions the spinner has, and on how many of them are a 5. The question, as stated, is incomplete and cannot be answered. Please restate the question.
Total number of possible stops = 8Number of successful stops = 2 (stops on 3 or on 6 are successful)Probability = 2/8 = 25%
∙It will be spun on a number less than 10 in 75 times if you spin it 100 times.Explanation:Let x be the random variable, x = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12}.The probability for any outcome is P(x) = 1/12. It is a flat probability distribution.The probability that when you spin the spinner the outcome is a number greater than10 is:P(10 ≤ x ≤ 12) = P(x = 10) + P(x = 11) + P(x = 12 ) = 3/12 = 1/4The probability of the complement event (that the outcome is a number smaller than 10) is: P(x < 10) = 1 - 1/4 = 3/4.So the expected number of times the spinner outcome will be a number smaller than 10 is:P(No. outcomes x
It is (the number of sectors which are numbered 2) divided by 6
3 in 10.
250
0.46
For an ordinary number cube, the answer is 1/6