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There is a 2 in 5 chance that the spinner will stop in a red section.

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What is the probability that the spinner will stop on 1-4?

The depends on what other numbers exist on the spinner. If there are a total of six numbers on the spinner, for instance, the probability of spinning a 1-4 is 2 in 3.


If you spin a spinner 400 times about how many times would you expect to stop on a vowel?

To determine how many times you would expect to stop on a vowel when spinning a spinner 400 times, you first need to know the number of vowels on the spinner. Assuming the spinner has an equal chance of landing on each section and contains vowels, calculate the probability of landing on a vowel. Multiply that probability by 400 to get the expected number of times you would land on a vowel. For example, if there are 5 vowels out of 10 sections, the expectation would be 400 x (5/10) = 200 times.


The face of the spinner is divided into six congrunt sectors. If the spinner is spun once what is the chance that it will stop on 2?

It is (the number of sectors which are numbered 2) divided by 6


If you have a spinner with 10 equal sides what is the proabability that it will stop on a number more than 7?

3 in 10.


What probability that a rolled dot cube will stop with exactly two dots on top?

When rolling a standard six-sided die (dot cube), the probability of any specific outcome, including landing with exactly two dots on top, is determined by the number of favorable outcomes divided by the total number of possible outcomes. There is one face with two dots, and there are six possible faces in total. Therefore, the probability of rolling a die and having it stop with exactly two dots on top is 1/6.

Related Questions

What is the probability that the spinner will stop on 1-4?

The depends on what other numbers exist on the spinner. If there are a total of six numbers on the spinner, for instance, the probability of spinning a 1-4 is 2 in 3.


If you spin the spinner once what is the probability that it will stop on A?

2/3


A spinner has equal regions numbered 1 through 21 What is the probability that the spinner will stop on an even number or a multiple of 3?

17 out of 21


If the spinner is spun twice what is the probability that the arrow will stop on an even number both times?

It depends on how many points there are that the spinner can land on. If there are 8, for example, the probability would be 8/16, or 1/2...


What is the probability that this spinner will stop on a 5?

It depends on how many positions the spinner has, and on how many of them are a 5. The question, as stated, is incomplete and cannot be answered. Please restate the question.


What is the probability that the spinner stop in multiple of 3. The spinner is numbered 1 through 8?

Total number of possible stops = 8Number of successful stops = 2 (stops on 3 or on 6 are successful)Probability = 2/8 = 25%


If you spin a spinner 400 times about how many times would you expect to stop on a vowel?

To determine how many times you would expect to stop on a vowel when spinning a spinner 400 times, you first need to know the number of vowels on the spinner. Assuming the spinner has an equal chance of landing on each section and contains vowels, calculate the probability of landing on a vowel. Multiply that probability by 400 to get the expected number of times you would land on a vowel. For example, if there are 5 vowels out of 10 sections, the expectation would be 400 x (5/10) = 200 times.


The spinner is divided into 12 equal parts if you spin the spinner 100 times how many times do you expect the spinner to stop on a number less than 10?

&#8729;It will be spun on a number less than 10 in 75 times if you spin it 100 times.Explanation:Let x be the random variable, x = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12}.The probability for any outcome is P(x) = 1/12. It is a flat probability distribution.The probability that when you spin the spinner the outcome is a number greater than10 is:P(10 &le; x &le; 12) = P(x = 10) + P(x = 11) + P(x = 12 ) = 3/12 = 1/4The probability of the complement event (that the outcome is a number smaller than 10) is: P(x < 10) = 1 - 1/4 = 3/4.So the expected number of times the spinner outcome will be a number smaller than 10 is:P(No. outcomes x


The face of the spinner is divided into six congrunt sectors. If the spinner is spun once what is the chance that it will stop on 2?

It is (the number of sectors which are numbered 2) divided by 6


If you have a spinner with 10 equal sides what is the proabability that it will stop on a number more than 7?

3 in 10.


If you spin a spinner 400 times about how many times would yu expect it to stop on a vowel?

250


Jake’s drive to work includes 2 sets of traffic lights. The probability that he has to stop at the first set is 0.3. The probability that he is stopped at the second set is 0.4. What is the probability that he is only stopped at one set of lights?

0.46