2/3
250
777 divided 7 Easy! 1st. Draw a bus stop Then on one side of the bus stop write 7 The other side write 777 After that how many times can 7 go into 7 that's 1 then how many times dose 7 go into 7 once then how many times dose 7 go into 7 once so the answer is 111!
A stop sign is hexagonal (six sides).A stop sign has 8 sides!
it looks like a stop sign a stop signits like a stop sign
A stop sign.A stop sign is an example of an octagon.
There is a 2 in 5 chance that the spinner will stop in a red section.
The depends on what other numbers exist on the spinner. If there are a total of six numbers on the spinner, for instance, the probability of spinning a 1-4 is 2 in 3.
17 out of 21
To determine how many times you would expect to stop on a vowel when spinning a spinner 400 times, you first need to know the number of vowels on the spinner. Assuming the spinner has an equal chance of landing on each section and contains vowels, calculate the probability of landing on a vowel. Multiply that probability by 400 to get the expected number of times you would land on a vowel. For example, if there are 5 vowels out of 10 sections, the expectation would be 400 x (5/10) = 200 times.
It depends on how many points there are that the spinner can land on. If there are 8, for example, the probability would be 8/16, or 1/2...
It depends on how many positions the spinner has, and on how many of them are a 5. The question, as stated, is incomplete and cannot be answered. Please restate the question.
Total number of possible stops = 8Number of successful stops = 2 (stops on 3 or on 6 are successful)Probability = 2/8 = 25%
250
∙It will be spun on a number less than 10 in 75 times if you spin it 100 times.Explanation:Let x be the random variable, x = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12}.The probability for any outcome is P(x) = 1/12. It is a flat probability distribution.The probability that when you spin the spinner the outcome is a number greater than10 is:P(10 ≤ x ≤ 12) = P(x = 10) + P(x = 11) + P(x = 12 ) = 3/12 = 1/4The probability of the complement event (that the outcome is a number smaller than 10) is: P(x < 10) = 1 - 1/4 = 3/4.So the expected number of times the spinner outcome will be a number smaller than 10 is:P(No. outcomes x
It is (the number of sectors which are numbered 2) divided by 6
To increase the spin, pull in your arms and they will stop slowing the spin down. Keeping them out will slow the spin down and you will spin for a smaller period of time. To stop the spin, stick your toe-pick into the ice, and you will stop. I hoped that helped you! :D
It depends on the circumstances. Some good strategies:If you're the first spinner, you'll want to stop at 65 cents or higher. Spinning again will put you at a high risk of going over.If you're the second or third spinner, or it's a spin-off, and you get a number that is higher than your opponent's number, stop.If both opponents have gone over, just take one spin and hope for the $1.00.If you get $1.00 in one spin or a combination of two, you get $1,000 and a bonus spin. In your bonus spin, if you land on a green space (5 or 15 cents), you win $10,000, and if you land on $1.00 again, you win $25,000.