1.2PARTIAL SOLUTION:7/9 = 14/15n7(15n) = (14)(9)105n = 126n = 1.2
Mean = (sum of the n numbers)/n
it adds one more each time. 1+2=3 3+3=6 6+4=10 10+5=15 the next one would be 15+6=21------------------------------------------------With U{n} = (7n⁵ - 105n⁴ + 595n³ - 1555n² + 1938n - 840)/40U{1, ..., 5} = {1, 3, 6, 10, 15}U{6} = 42However, I suspect the rule your teacher wants is that it is the triangular numbers given by U{n} = ½n(n + 1)
Mean = Total of the numbers / n So total of the numbers = n*mean
The sum of the first n natural numbers is n*(n+1)/2 There are n numbers so their mean = (n+1)/2
1.2PARTIAL SOLUTION:7/9 = 14/15n7(15n) = (14)(9)105n = 126n = 1.2
A force of 105 Newtons.
Mean = (sum of the n numbers)/n
it adds one more each time. 1+2=3 3+3=6 6+4=10 10+5=15 the next one would be 15+6=21------------------------------------------------With U{n} = (7n⁵ - 105n⁴ + 595n³ - 1555n² + 1938n - 840)/40U{1, ..., 5} = {1, 3, 6, 10, 15}U{6} = 42However, I suspect the rule your teacher wants is that it is the triangular numbers given by U{n} = ½n(n + 1)
Mean = Total of the numbers / n So total of the numbers = n*mean
(5*105N)*509m=267225Nm Force times distance = Work (Work = Energy) Power = Work / Time
The sum of the first n natural numbers is n*(n+1)/2 There are n numbers so their mean = (n+1)/2
#includevoid mean(int[],int);void main(){int n,a[24];printf("Enter the number of terms to find mean\n");scanf("%d",&n);printf("Enter the numbers\n");for(i=0;i
1n=n 1xn if n mean 64, n=64, 1xn=64,1n=64
do you mean n factorial, n! perhaps.
The sum from 1 to n is n*(n+1)/2In this case that mean 20*21/2 = 210The sum from 1 to n is n*(n+1)/2In this case that mean 20*21/2 = 210The sum from 1 to n is n*(n+1)/2In this case that mean 20*21/2 = 210The sum from 1 to n is n*(n+1)/2In this case that mean 20*21/2 = 210
n^3 mean a number Squared by 3