it stands for sides
s x s or s + s + s + s
If the side of the square is of length s then the perimeter is 4*s.
It has to do with the surface area formula: To find the total surface area of a pyramid, use this equation: Surface Area = B + 1/2 * P * s B = base area P = perimeter of the base s = slant height To find the volume of a Pyramid, substitute into this equation: V=1/3Bh B=base area h=height of pyramid
To calculate the surface area of a square pyramid, you need to find the area of the base (which is a square) and the area of the four triangular faces. The formula for the surface area of a square pyramid is SA = s^2 + 2sl, where s is the side length of the base and l is the slant height. In this case, with a base side length of 8 inches and a slant height of 15 inches, the surface area would be SA = 8^2 + 2(8)(15) = 64 + 240 = 304 square inches.
The formula for the volume of a pyramid such as you described would be: V = 1/3Ah where A is the area of the base (a square in this case) and h is the height of the pyramid. You know the volume and the height, so you can plug them into that formula to solve for A, the area of the square base: 63690 = 1/3A(30). A = 6369 square meters. Knowing the area of the square, and the fact that the formula for the area of a square is A = s2 where s is the length of a side, you can find the length of s by taking the square root of 6369. s = about 79.8 meters. The next steps will require some thinking about what that pyramid looks like and what the length of a lateral height segment would represent. Drawing a diagram often helps. If I understand correctly what you mean by "lateral height segment" of the pyramid, meaning the length of the segment from the center of a side at the bottom to the vertex at the top, that length would represent the hypotenuse of a right triangle whose legs are 30 meters (the inside height of the pyramid) and about 39.9 meters (half the length of a side, in other words the distance from the point at the center of the base to the center of the side). You can use the Pythagorean theorem to find that length: c2 = a2 + b2 c2 = 302 + 39.92 c2 = 900 + 1592 c2 = 2492 c = 49.9 meters (approximately)
A = S squared is the formula for area of a square A = area S = lenght of side
To find the length of one side of the square base of a regular pyramid with a volume of 300 cubic feet, we use the formula for the volume of a pyramid: ( V = \frac{1}{3} \times \text{Base Area} \times \text{Height} ). Assuming the base is a square, the base area is ( s^2 ) (where ( s ) is the side length). However, without the height of the pyramid, we cannot directly calculate ( s ). If the height were known, we could rearrange the formula to solve for ( s ).
LA = 1/2psnewtest3
Call the length of the base s and the slant height of one triangle l SA = s2 + 2sl
there both flat
The formula for the area of a square is: s * s where s = length of a side The formula for the perimeter of a square is: 4 * s where s = length of a side
s +s+s+s
s +s+s+s
s x s or s + s + s + s
If the side of the square is of length s then the perimeter is 4*s.
SA = s2 + 2 × s × l
Volume: If it's a square-based pyramid then its just "the base times the height, divided by 3" or in short b2h/3 where b is one side of the base. and h is height. Surface area: 2bs+b2 where s is the perpendicular height from the bottom of any one of the triangles, to the top of the tip.