That when x=3, y=15.
That when x=3, y=15.
The ordered pair is (6, 3).
The pair (2, 3) is the same as the pair (3, 2) but the ORDERED pair (2, 3) is NOT the same as the ORDERED pair (3, 2). In an ordered pair the order of the numbers does matter.
Given the ordered pair (3, y), what value of ywould make the ordered pair a solution of the equation 4x − 2y = 24?12
The first number in an ordered pair is the x-coordinate. Your very welcome i came along and told you the answer aren't you! <3
That when x=3, y=15.
The ordered pair is (6, 3).
The pair (2, 3) is the same as the pair (3, 2) but the ORDERED pair (2, 3) is NOT the same as the ORDERED pair (3, 2). In an ordered pair the order of the numbers does matter.
Given the ordered pair (3, y), what value of ywould make the ordered pair a solution of the equation 4x − 2y = 24?12
There are an infinite number of ordered pairs. (-5, -7) is one pair
The first number in an ordered pair is the x-coordinate. Your very welcome i came along and told you the answer aren't you! <3
The ordered pair is (1, 3).
The first number in an ordered pair is the x-coordinate. Your very welcome i came along and told you the answer aren't you! <3
An ordered pair is a list of two numbers, in which the order matters. For example, (5, 2) is an ordered pair; this pair is not the same as (2, 5). For comparison, for the numbers in a set the order does not matter.
x - y = 1 so x = y+1 15(y+1) - 4y = -3 15y + 15 - 4y = -3 11y = 12 y = 12/11 x = 12/11 + 1 = 23/11 Ordered pair, then, is (23/11, 12/11)
You can easily test any ordered pair that someone may offer you, to determinewhether the pair is part of the graph of the function [ y = 3 - x ].Simply check to see whether the sum of the two members of the ordered pair is 3.If yes, and only if yes, then the pair is part of the graph of the function.
To determine an ordered pair that could be a solution to an inequality, you need to substitute the values of the ordered pair into the inequality and check if it satisfies the condition. For example, if the inequality is (y < 2x + 3) and the ordered pair is (1, 4), you would substitute (x = 1) and (y = 4) to see if (4 < 2(1) + 3) holds true. If it does, then (1, 4) is a solution; if not, you would need to try another pair.