if the statement is : if p then q converse: if q then p inverse: if not p then not q contrapositive: if not q then not
A conditional statement is much like the transitive property in geometry, meaning if: P>Q and ~N>P then you can conclude: if ~N>Q
p divided by q.
q only if p. The converse of a statement is just swapping the places of the two terms.
It in Math, (Geometry) If p implies q is a true conditional statement and not q is true, then not p is true.
It means the statement P implies Q.
Converse: If p r then p q and q rContrapositive: If not p r then not (p q and q r) = If not p r then not p q or not q r Inverse: If not p q and q r then not p r = If not p q or not q r then not p r
"if p then q" is denoted as p → q. ~p denotes negation of p. So inverse of above statement is ~p → ~q, and contrapositive is ~q →~p. ˄ denotes 'and' ˅ denotes 'or'
if the statement is : if p then q converse: if q then p inverse: if not p then not q contrapositive: if not q then not
No, it is not valid because there is no operator between P and q.
Let us consider "This statement is false." This quotation could also be read as "This, which is a statement, is false," which could by extent be read as "This is a statement and it is false." Let's call this quotation P. The statement that P is a statement will be called Q. If S, then R and S equals R; therefore, if Q, then P equals not-P (since it equals Q and not-P). Since P cannot equal not-P, we know that Q is false. Since Q is false, P is not a statement. Since P says that it is a statement, which is false, P itself is false. Note that being false does not make P a statement; all things that are statements are true or false, but it is not necessarily true that all things that are true or false are statements. In summary: "this statement is false" is false because it says it's a statement but it isn't.
A+
P! / q!(p-q)!
. p . . . . . q. 0 . . . . . 1. 1 . . . . . 0
Any fraction p/q where p is an integer and q is a non-zero integer is rational.
a syllogism
The statement "if not p, then not q" always has the same truth value as the conditional "if p, then q." They are logically equivalent.