P! / q!(p-q)!
a syllogism
This is an incomplete statement. Your question cannot be answered.
If B is between P and Q, then: P<B<Q
4(p + q), or 4p + 4q
Converse: If p r then p q and q rContrapositive: If not p r then not (p q and q r) = If not p r then not p q or not q r Inverse: If not p q and q r then not p r = If not p q or not q r then not p r
"if p then q" is denoted as p → q. ~p denotes negation of p. So inverse of above statement is ~p → ~q, and contrapositive is ~q →~p. ˄ denotes 'and' ˅ denotes 'or'
if the statement is : if p then q converse: if q then p inverse: if not p then not q contrapositive: if not q then not
Not sure I can do a table here but: P True, Q True then P -> Q True P True, Q False then P -> Q False P False, Q True then P -> Q True P False, Q False then P -> Q True It is the same as not(P) OR Q
No, it is not valid because there is no operator between P and q.
I guess you mean q → p (as in the logic operator: q implies p).To create this truth table, you run over all truth values for q and p (that is whether each statement is True or False) and calculate the value of the operator. You can use True/False, T/F, 1/0, √/X, etc as long as you are consistent for the symbol used for True and the symbol used for False (the first 3 suggestions given are the usual ones used).For implies:if you have a true statement, then it can only imply a true statement to be truebut a negative statement can imply either a true statement or a false one to be truegiving:. q . . p . q→p--------------. 0 . . 0 . . 1 .. 0 . . 1 . . 1 .. 1 . . 0 . . 0 .. 1 . . 1 . . 1 .
A+
P! / q!(p-q)!
. p . . . . . q. 0 . . . . . 1. 1 . . . . . 0
Let us consider "This statement is false." This quotation could also be read as "This, which is a statement, is false," which could by extent be read as "This is a statement and it is false." Let's call this quotation P. The statement that P is a statement will be called Q. If S, then R and S equals R; therefore, if Q, then P equals not-P (since it equals Q and not-P). Since P cannot equal not-P, we know that Q is false. Since Q is false, P is not a statement. Since P says that it is a statement, which is false, P itself is false. Note that being false does not make P a statement; all things that are statements are true or false, but it is not necessarily true that all things that are true or false are statements. In summary: "this statement is false" is false because it says it's a statement but it isn't.
Any fraction p/q where p is an integer and q is a non-zero integer is rational.
a syllogism