2n+4/2 term 1 = 3 term 2 = 4 term 3 = 5 term 4 = 6
2n+3. If 5 is the first term, then it is 2n + 3 (2×1 = 2 + 3 = 5 and 2×2 + 3 = 7)
The nth term is: 5-2n
The Nth term of tn = 2n + 3 is 2N + 3. Replace (substitute) the n by the term number to get its value. t1 = 2 x 1 + 3 = 5 t2 = 2 x 2 + 3 = 7 t3 = 2 x 3 + 3 = 9 etc.
It is: 2n+4
2n-1 to the tenth term = 1
3=2n
The nth term is: 2n+7 and so the next number will be 19
The nth term of the sequence is 2n + 1.
1st term= 3 2nd term = 5 Nth term = 2n+1 10th term= 21 = 2(10)+1
Un = 2n - 8 Un = 2n - 8 Un = 2n - 8 Un = 2n - 8
The nth term is 2n+5 and so the next number is 17
n = 1, 2n = 2 n = 2, 2n = 4 n = 3, 2n = 6 2, 4, 6, ..., 2n where n = 1, 2, 3, ... This is an arithmetic sequence, where the first term is 2 and the common difference is 2.
151
Each number in this sequence is twice the previous number. The nth. term is 2n-1.Each number in this sequence is twice the previous number. The nth. term is 2n-1.Each number in this sequence is twice the previous number. The nth. term is 2n-1.Each number in this sequence is twice the previous number. The nth. term is 2n-1.
Ok, take the formula dn+(a-d) this is just when having a sequence with a common difference dn+(a-d) when d=common difference, a=the 1st term, n=the nth term - you have the sequence 2, 4, 6, 8... and you want to find the nth term therefore: dn+(a-d) 2n+(2-2) 2n Let's assume you want to find the 5th term (in this case, the following number in the sequence) 2(5) = 10 (so the fifth term is 10)
2n+4/2 term 1 = 3 term 2 = 4 term 3 = 5 term 4 = 6