2n+4/2
term 1 = 3
term 2 = 4
term 3 = 5
term 4 = 6
The first four terms are 3 9 27 81 and 729 is the 6th term.
9, 10, 11 and 12
a, ar, ar^2 and ar^3 where a and r are constants.
If you mean nth term 2n then the 1st four terms are 2 4 6 and 8
1, 16, 81, 256 14641 is the 11th term.
5
The first four terms are 3 9 27 81 and 729 is the 6th term.
2
6
9, 10, 11 and 12
a, ar, ar^2 and ar^3 where a and r are constants.
29
If you mean nth term 2n then the 1st four terms are 2 4 6 and 8
We need help with answering this question.
1, 16, 81, 256 14641 is the 11th term.
To find the first four terms of the sequence defined by ( a_n = 2n - 8 ), we can substitute ( n = 1, 2, 3, ) and ( 4 ). For ( n = 1 ): ( a_1 = 2(1) - 8 = 2 - 8 = -6 ) For ( n = 2 ): ( a_2 = 2(2) - 8 = 4 - 8 = -4 ) For ( n = 3 ): ( a_3 = 2(3) - 8 = 6 - 8 = -2 ) For ( n = 4 ): ( a_4 = 2(4) - 8 = 8 - 8 = 0 ) Thus, the first four terms of the sequence are (-6, -4, -2, 0).
Expressed in lowest terms, four and a half divided by five and three sixths = 9/11