Both equations are equal and so: 3x+1 = 2x+3 3x-2x = 3-1 x = 2 and by substituting y = 7
I think you mean (3x ± 1)^2 = (3x+1)(3x-1)?
10x + 5 which is also equal to 5(2x + 1)
(2, -1)
No. they are parallel, since the slopes are both equal in this case 3. To be perpendicular the product of the slopes of both lines is equal to -1 (i.e., m1*m2 = -1).
Both equations are equal and so: 3x+1 = 2x+3 3x-2x = 3-1 x = 2 and by substituting y = 7
I think you mean (3x ± 1)^2 = (3x+1)(3x-1)?
10x + 5 which is also equal to 5(2x + 1)
(2, -1)
No. they are parallel, since the slopes are both equal in this case 3. To be perpendicular the product of the slopes of both lines is equal to -1 (i.e., m1*m2 = -1).
y = 3X - 1
y = 3x + 1
If: 3x+5 = 4x+1 Then: x = 4
(1, 1)
x + 2 = 3x-1 -2x = -3x = 1,5
It is called the commutative property, a + b = b + a
1