Each element is the mean of the corresponding elements. Thus, the mean of (x1, y1) and ( x2, y2) is [( x1 + x2)/2, (y1 + y2)/2]
I think you have missed out an equals sign. If you mean x2 + y2 = 16, then the radius is 4.
If you mean: y2+5y+6 then it is (y+2)(y+3) when factored completely
I think you have missed out an equals sign. If you mean x2 + y2 = 16, then the radius is 4.
y6 x y2 y4 x y4 y2 x y2 x y4 y2 x y2 x y2 x y2
Each element is the mean of the corresponding elements. Thus, the mean of (x1, y1) and ( x2, y2) is [( x1 + x2)/2, (y1 + y2)/2]
It means the average
y2 + y2 = 2y2
I think you have missed out an equals sign. If you mean x2 + y2 = 16, then the radius is 4.
If you mean: y2+5y+6 then it is (y+2)(y+3) when factored completely
I think you have missed out an equals sign. If you mean x2 + y2 = 16, then the radius is 4.
y6 x y2 y4 x y4 y2 x y2 x y4 y2 x y2 x y2 x y2
8
4x-y2 = 2
It is 37 - (-52) = 37 + 52 = 89 If they are coordinates that got mangled: The distance between (-5, 2) and (3, 7) is: distance = √((x2 - x1)² + (y2 - y1)²) = √((3 - -5)² + (7 - 2)²) = √(8² + 5²) = √ 89 ≈ 9.434
88 + 5y - y2 66 - 3y + y2 Subtract: 22 + 8y -2y2
If you mean y2+8y+7=0 then it is a quadratic. y2+8y+7+9-9=0 y2+8y+16-9=0 (y+4)2=9 y+4=3 , y+4=-3 y=-1 , y=-7 So y can equal -1 or -7.