88 + 5y - y2 66 - 3y + y2 Subtract: 22 + 8y -2y2
The equation of a circle centered at the origin is x2 + y2 = r2; in this case, x2 + y2 = 64.The equation of a circle centered at the origin is x2 + y2 = r2; in this case, x2 + y2 = 64.The equation of a circle centered at the origin is x2 + y2 = r2; in this case, x2 + y2 = 64.The equation of a circle centered at the origin is x2 + y2 = r2; in this case, x2 + y2 = 64.
5
y2 = 4ax is as broken down it can get because there are no like terms that can be combined.
An identity equation has infinite solutions.
y2 = 169 Square root both sides: y = 13
X2 + Y2 = 2X = sqrt(2 - Y2)Y can not be greater than 2 or a complex number would be yielded from under the radical. So, - infinity to 2, or something like that for Y's value.Same procedure for X.
No, because there is more than one solution: y2 = x2 y = ±(x2)1/2 y = ±x Because there are multiple solutions for a single value of x, this does not qualify as a function.
y2 + y2 = 2y2
That there are no whole number solutions to the equation: xn + yn = zn when n > 2. If n = 2 this is: x2 + y2 = z2 is known as Pythagoras' Theorem, and has many whole number solutions, eg 32 + 42 = 52, 52 + 122 = 132.
To graph y2 = -3x, first solve for y. Doing this results in two solutions: y = √(-3x) and y = -√(-3x) Put the first solution into y1 and the second solution into y2. The two solutions together should form a sideways parabola.
y=5xx2+y2=26Substitute the first equation into the second for y.x2 + (5x)2 = 26x2 + 25x2 = 2626x2 = 26x2 = 1x = SQRT(1) = 1 & -1y = 5*1 = 5y = 5*-1 = -5So the solutions are: (1,5) & (-1, -5)
y6 x y2 y4 x y4 y2 x y2 x y4 y2 x y2 x y2 x y2
y2 + 4y -12 = 0 y2 + 6y - 2y -12 = 0 y(y + 6) -2(y +6) = 0 (y -2) x (y + 6) = 0 Hence (y-2) is zero which gives y = 2 or (y + 6) is zero which gives y = -6 The roots or solutions to the equation y2 + 4y -12 = 0 are y = 2 and y = -6
Equations of the form y2 = x3 + ax + b are powerful mathematical tools. The Birch and Swinnerton-Dyer conjecture tells how to determine how many solutions they have in the realm of rational numbers-information that could solve a host of problems, if the conjecture is true.
If: 2x+y = 5 and x2-y2 = 3 Then the solutions work out as: (2, 1) and ( 14/3, -13/3)
4x-y2 = 2