The answer depends on what is already known about the two triangles.
"What else" implies there is already something that is congruent. But since you have not bothered to share that crucial bit of information, I cannot provide a more useful answer. no correct
To show that triangles ABC and DEF are congruent by the AAS (Angle-Angle-Side) theorem, you need to establish that two angles and the non-included side of one triangle are congruent to the corresponding two angles and the non-included side of the other triangle. If you have already shown two angles congruent, you would need to prove that one of the sides opposite one of those angles in triangle ABC is congruent to the corresponding side in triangle DEF. This additional information will complete the criteria for applying the AAS theorem.
Nothing else, the angle-angle-side is sufficient to show the triangles are congruent. With two corresponding angles are equal, the third angles in the triangles by definition (the sum of the three angles in a triangle is 180o) must be equal making the triangles similar. If a corresponding pair of sides are also equal, then the other two corresponding pairs of sides will be equal.
Because Corresponding Parts of Congruent Triangles, there are five ways to prove that two triangles are congruent. Show that all sides are congruent. (SSS) Show that two sides and their common angle are congruent. (SAS) Show that two angles and their common side are congruent. (ASA) Show that two angles and one of the non common sides are congruent. (AAS) Show that the hypotenuse and one leg of a right triangle are congruent. (HL)
__ - __ AC = XZ = is the similar sign
Angle "A" is congruent to Angle "D"
The answer depends on what is already known about the two triangles.
Bc= qr
bc yz
Su jL
That depends on which sides have not been proven congruent yet.
"What else" implies there is already something that is congruent. But since you have not bothered to share that crucial bit of information, I cannot provide a more useful answer.
"What else" implies there is already something that is congruent. But since you have not bothered to share that crucial bit of information, I cannot provide a more useful answer.
Line segment BC is congruent to Line Segment YZ
We don't know what has already been proven congruent, sowe're in no position to be able to say what elseis required.
bh=ws