2+2+2+2+2-7 This is an equation that uses 5 2's yet equals 3.
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(22/2+2)x2
It is a simple linear equation in 's'. Its solution is the number that 's' must bein order to make it a true statement. The solution may be found like this:4s + 10 = 2s + 2Subtract 10 from each side of the equation:4s = 2s - 8Subtract 2s from each side:2s = -8Divide each side by 2 :s = -4
22 + 22 - 2 = 42
2s + 17 = 2s + 17 1) First, you want to start on the left side of the equation and subtract 17 from both sides. 2s = 2s 2) Then, you take the 2 on the left side and divide it on both sides. s = s 3) You are left with s (Or 1s) on both sides, so s = 1.
2r + 2s = 50 2r - s = 17 therefore 4r - 2s = 34 Add so that you can eliminate one of the variables: 2r + 2s = 50 4r - 2s = 34 ---------------- 6r + 0s = 84 Solve for r: 6r = 84 r = 14 Substitute r into one of the original equations: 2(14) + 2s = 50 28 + 2s = 50 2s = 22 s = 11 Doublecheck with the other original equation: 2(14) - 11 = 28 - 11 = 17
Points: (s, 2s) and (3s, 8s) Slope: (8s-2s)/(3s-s) = 6s/2s = 3 Perpendicular slope: -1/3 Midpoint: (s+3s)/2 and (2s+8s)/2 = (2s, 5s) Equation: y-5s = -1/3(x-2s) => 3y-15s = -1(x-2s) => 3y = -x+17x Perpendicular bisector equation in its general form: x+3y-17s = 0
To use five 2s to make 3, you can employ a mathematical operation like exponentiation. One way to achieve this is by arranging the 2s as follows: (2^2) - (2/2) = 3. This expression involves raising 2 to the power of 2 (which equals 4) and then subtracting the result of dividing 2 by 2 from it, resulting in 3.
It can't be solved because it's not an equation.
Well, honey, if you want to make five 2s equal five, all you gotta do is write it as 2 + 2 + 2/2 = 5. Simple math, darling. Just divide one of those pesky 2s by 2 and voila, you've got yourself a nice little equation that adds up to 5.
2s - 12 + 2s = 4s - 124s - 12 = 4s - 124s = 4ss = s==========this is an identity and any number can be s
17
5s - 6 = 2s, ie 5s - 2s = 6, ie 3s = 6, ie s = 2