414
Point: (2, 17)Slope: 7Equation: y = 2x+13
The equation is: y --2 = -2(x-3) => y = -2x+4
2-3
Y=2x+6
Write the equation of a line in slope-intercept form that has a slope of -2 and passes through the point (2, -8).
414
Point: (2, 17)Slope: 7Equation: y = 2x+13
The equation works out as: y = 5x+7
y = 7
The equation in point slope of the line which passes through -2 -3 and is parallel to 3x plus 2y 10 is y=-1.5x.
The equation is: y --2 = -2(x-3) => y = -2x+4
2-3
Y=2x+6
If you mean slope of -3 and a point of (2, 4) then the equation is y = -3x+10
Y=mx+b
y = -2x + 5