Q: A line passes through the point and has a slope of Write an equation for this line?

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Point: (1, 4) Slope: -3 Equation: y = -3x+7

It passes through Quadrants II and IV. It also passes through the origin ... the point where the 'x' and 'y' axes cross. At that point, it's in all four quadrants.

The standard equation for a straight line is y = mx + c. Let this be the equation of the original line. Note that m and c are known values. Let the given point coordinates be (a,b)Two straight lines are perpendicular if the product of their gradients (slopes) is -1.The slope (m1) of the perpendicular line is therefore m1 = -1/mWhen y = b then x = a so the equation for the perpendicular line is y = m1x + d, and substituting gives : b = -a/m + d and this will enable d to be calculated.NOTE : In the absence of information for the equation of the original line and the coordinates of the given point then this is a general rather than a specific answer.

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Write the equation of a line in slope-intercept form that has a slope of -2 and passes through the point (2, -8).

write an equation that has a slope 7 and passes through the point (2,17)

Y=2x+6

(0,-6) m=-2

Write an equation in slope-intercept form for the line that passes through the given point and is parallel to the given line (-7,3); x=4

Point: (2, 4) Slope: -3 Equation: y = -3x+10

Yes, I could, if I knew the slope of the line given.

If given simply the slope of a line and a point through which it passes, and then told to find the equation of the line, one of the easiest ways of doing so is to use the point-slope formula.

If given simply the slope of a line and a point through which it passes, and then told to find the equation of the line, one of the easiest ways of doing so is to use the point-slope formula.

If given simply the slope of a line and a point through which it passes, and then told to find the equation of the line, one of the easiest ways of doing so is to use the point-slope formula.