Y=mx+b
(-8,-7)
A line passes through the point (10,2) and has a slope of 1/2
(2,-6) -5/2
Center
-40
33
Point: (1, 4) Slope: -3 Equation: y = -3x+7
It passes through Quadrants II and IV. It also passes through the origin ... the point where the 'x' and 'y' axes cross. At that point, it's in all four quadrants.
y = 3x - 3
sda
Write the equation of a line in slope-intercept form that has a slope of -2 and passes through the point (2, -8).
write an equation that has a slope 7 and passes through the point (2,17)
Y=2x+6
(0,-6) m=-2
Write an equation in slope-intercept form for the line that passes through the given point and is parallel to the given line (-7,3); x=4
Point: (2, 4) Slope: -3 Equation: y = -3x+10
Yes, I could, if I knew the slope of the line given.
If given simply the slope of a line and a point through which it passes, and then told to find the equation of the line, one of the easiest ways of doing so is to use the point-slope formula.
If given simply the slope of a line and a point through which it passes, and then told to find the equation of the line, one of the easiest ways of doing so is to use the point-slope formula.
If given simply the slope of a line and a point through which it passes, and then told to find the equation of the line, one of the easiest ways of doing so is to use the point-slope formula.
If given simply the slope of a line and a point through which it passes, and then told to find the equation of the line, one of the easiest ways of doing so is to use the point-slope formula.