You need the height as well to find the area, but the proper equation would be
A= 5.5h
A right triangle with a hypotenuse of length 15 and a leg of length 8 has an area of: 50.75 units2
The area is approximately 71.2 units2
a delta's a triangle, so the area of a triangle is bh/2
Area of Triangle= 1/2(ab) You must multiply length b and length a together and then half it.
The area of a triangle cannot be determined by its length and withgt or width, even. You need the length and the perpendicular height.
The area of the cross section (the triangle) muliplied by the length of the prism. Area of triangle= 0.5 x base x height Then mulitply by the length the prism goes back
you multiply the length times the width and then divide by 2, the equation looks like this... LxS/2
A right triangle with a hypotenuse of length 15 and a leg of length 8 has an area of: 50.75 units2
If the given length is the measure length of the base of the triangle, then the area of the triangle is: A = (bh)/2 = (10 x 20)/2 = 100.
The area is approximately 71.2 units2
with a tape measure To calculate the area of a rectangle, you multiply the length times the width. To calculate the area of a square, you multiply one side times another side. To calculate the area of a circle, you multiply the diameter times pi (that's 3.1416). To calculate the area of a triangle, you multiply the height times the base, and divide by 2.
To get the area of a triangle you multiply length by width and divide by two.
A right triangle has a hypotenuse of length 10 and a leg of length 7 has an area of: 24.99 units2
Area of a right triangle = (1/2 the length of one leg) x (length of the other leg)
a delta's a triangle, so the area of a triangle is bh/2
Area of triangle * 2 + perimeter of triangle * length.
The area of triangle is : 60.0