Let the five-digit number be represented as ( x ). We need to find ( x ) such that ( 4x ) equals the reverse of ( x ).
We can express ( x ) as ( 10^4a + 10^3b + 10^2c + 10d + e ) (where ( a, b, c, d, e ) are the digits of ( x )), then ( 4x ) becomes ( 4(10^4a + 10^3b + 10^2c + 10d + e) ).
After exploring possible five-digit values, the number ( 21978 ) satisfies the condition because ( 4 \times 21978 = 87912 ), which is indeed ( 21978 ) with its digits reversed.
whats the answer please??
38
you just carry the first number and add 5 to the second number
The number of partial products in multiplication depends on the number of digits in the factors being multiplied. In 1(a), if there are three digits in one factor, each digit contributes a partial product when multiplied by the other factor, resulting in three partial products. In 1(b), if one factor has two digits, it will produce only two partial products corresponding to its two digits. Thus, the difference in the number of partial products reflects the number of digits in the factors being multiplied.
731 and 137
The number is 21978. 21978 when multiplied by 4 which gives the result 87912 which is in reverse order.
36
Find a four digit number whose digits will be reversed when multiplied by nine?
whats the answer please??
When multiplying numbers with significant digits, count the total number of significant digits in each number being multiplied. The result should have the same number of significant digits as the number with the fewest significant digits. Round the final answer to that number of significant digits.
34.
2178
00000
You write the number and then follow it with the digits in reverse order.
36 is twice the product of its digits multiplied. 3 times 6 equals 18, and 18 times 2 equals 36.
Six.
38