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For all real numbers a b and c?
Blob
Show that the set of all real numbers is a group with respect to addition?
Closure: The sum of two real numbers is always a real number. Associativity: If a,b ,c are real numbers, then (a+b)+c = a+(b+c) Identity: 0 is the identity element since 0+a=a and a+0=a for any real number a. Inverse: Every real number (a) has an additive inverse (-a) since a + (-a) = 0 Those are the four requirements for a group.
How to evaluate 2a plus 6b?
2a + 6b = c, where a, b, and c are all numbers from the domain of your choice. Usually, in algebra, the real number set R is used as the domain. In this case, you would need to select values from R for a and b which will yield the value of c. Since this function is closed in the real number system, c will always be a real number, given that a and b are real numbers.
What is the name for all sets of numbers?
There is a hierarchy of sets:Counting numbersNatural numbers (N)Integers (Z)Rational numbers (Q)Real numbers (R)Complex numbers (C)Quaternions, and possibly more.
What is the sum of complex numbers?
In (a+bi) + (c+di), you add the real parts using the laws for real numbers and do the same for the imanginary parts. (a+c)+(b+d)i
Number a is 4676. number b is 10043 greater than A. Number C is 2610 less than B. What is th total value of numbers aband c?
Oh, dude, let's break this down. So, if number A is 4676, then number B is 10043 + 4676, which is like basic addition, right? And then number C is 2610 less than B, so you just subtract that from B. Add A, B, and C together, and you've got the total value. Math, man, it's wild.
For all real numbers a b and c?
Blob
Is the product of two imaginary numbers always an imaginary number?
If you are talking about pure imaginary numbers (a complex number with no real part) then no. Example: bi times ci where b and c are real numbers equals b*c*i² = b*c*(-1) = -b*c, which is a real number, because b & c & -1 are all real numbers. If you're talking about multiplying two complex numbers (a + bi)*(c + di), then the product will be complex, but it could be real or imaginary, depending on the values of a, b, c, & d.
What is the multiplycation law of exponents?
ab x ac = ab+c, where a, b, and c are all real numbers.
Show that the set of all real numbers is a group with respect to addition?
Closure: The sum of two real numbers is always a real number. Associativity: If a,b ,c are real numbers, then (a+b)+c = a+(b+c) Identity: 0 is the identity element since 0+a=a and a+0=a for any real number a. Inverse: Every real number (a) has an additive inverse (-a) since a + (-a) = 0 Those are the four requirements for a group.
When you use decimal which type of data is it?
Decimal numbers are real numbers. In C and C++ we use the float, double and long double data types to represent real numbers.
How to evaluate 2a plus 6b?
2a + 6b = c, where a, b, and c are all numbers from the domain of your choice. Usually, in algebra, the real number set R is used as the domain. In this case, you would need to select values from R for a and b which will yield the value of c. Since this function is closed in the real number system, c will always be a real number, given that a and b are real numbers.
What is the name for all sets of numbers?
There is a hierarchy of sets:Counting numbersNatural numbers (N)Integers (Z)Rational numbers (Q)Real numbers (R)Complex numbers (C)Quaternions, and possibly more.
What is the sum of complex numbers?
In (a+bi) + (c+di), you add the real parts using the laws for real numbers and do the same for the imanginary parts. (a+c)+(b+d)i
What is a definition for associative property of addition?
The property which states that for all real numbers a, b, and c, their sum is always the same, regardless of their grouping:(a + b) + c = a + (b + c)
What is the difference between real numbers and complex numbers?
Real numbers are a proper subset of complex numbers. In fact each complex number, z, can be represented as z = x +iy where x and y are real numbers and i is the imaginary square root of -1.Thus the set of complex numbers is the Cartesian product of two sets of real numbers. That is, C = R x R where C is the set of complex numbers and R is the set of real numbers. Limitations of this browser prevent me from writing that in a mathematically precise and more helpful fashion.
The sum of two complex numbers is always a complex number?
A "complex number" is a number of the form a+bi, where a and b are both real numbers and i is the principal square root of -1. Since b can be equal to 0, you see that the real numbers are a subset of the complex numbers. Similarly, since a can be zero, the imaginary numbers are a subset of the complex numbers. So let's take two complex numbers: a+bi and c+di (where a, b, c, and d are real). We add them together and we get: (a+c) + (b+d)i The sum of two real numbers is always real, so a+c is a real number and b+d is a real number, so the sum of two complex numbers is a complex number. What you may really be wondering is whether the sum of two non-real complex numbers can ever be a real number. The answer is yes: (3+2i) + (5-2i) = 8. In fact, the complex numbers form an algebraic field. The sum, difference, product, and quotient of any two complex numbers (except division by 0) is a complex number (keeping in mind the special case that both real and imaginary numbers are a subset of the complex numbers).
