If: 3x-5y+10 = 0 Then: -5y = -3x-10 And: y = 0.6x+2 in slope-intercept form
x=(-5y-1)/3
No.
(4, -1)
51
If: 3x-5y+10 = 0 Then: -5y = -3x-10 And: y = 0.6x+2 in slope-intercept form
no
3x+5y=48 5y=48-3x-3x+5y=12 -3x+(48-3x)=12-6x=-36x=65y=48-3(6)5y=30y=6(6,6)
x=(-5y-1)/3
No.
X = -2(13 + y) / 3x = 5y / 4 - 1
Get in slope intercept form. 3X + 5Y = 15 5Y = -3X + 15 Y = -3/5X + 3 -3/5 is the slope of this line and the line parallel to this line
(4, -1)
51
-3/5
-3x + 5y = 255y = 3x + 25y = 3x/5 + 5This is now in standard form. y = ax + b, where b is the y-intercept. In this case, the y-intercept is 5.
3X + 5Y = 75Y = - 3X + 7Y = (-3/5)X + 7/5==================equation of the line