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To make sure the smallest number is odd, call it (2x-1), which has to be odd.
Four consecutive odd numbers are . . . (2x-1) + (2x+1) + (2x+3) + (2x+5) = 19
8x + 8 = 19
8x = 11
x = 11/8
There is no solution that satisfies the conditions given in the question.
We should have suspected this as soon as we read the question, because we know that
an even number of odd numbers can't add up to an odd number.
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Pick four odd digits that add up to nineteen?
I won't tell you the answer, but here's a hint, you can use each number more than one time...
What is the largest four digit odd number whose four digits are even?
There is no such number. If the four digits are even, the entire number is even, not odd.
What is four eight-digit odd numbers whose last six digits have the sum of ten?
You can work this out pretty quick; just assemble the number in parts. We know the number must be odd, so the last digit has to be an odd one. Let's make it three: 3 Now we need to add five more digits that collectively add up to seven (giving us the sum of ten for our six digits. There's no limit of repetition limit, so we can simply say our numbers are 1, 1, 1, 2 and 2: 111223 That's our last six digits that add up to ten. To get four different eight-digit odd numbers, all we have to do is add four combinations of two digits on the beginning: 99111223 98111223 97111223 96111223
List the odd four digit numerals each containing the digits 3 4 5 6?
List the odd four-digit numerals,each containing the digits ,4,5 and 6.
What is the least four-digit odd number with no repeated digits?
1023
