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To find the fraction of four-digit natural numbers with an even product of their digits, we first note that a four-digit number ranges from 1000 to 9999, giving us a total of 9000 four-digit numbers. The product of the digits is even if at least one digit is even. The only case where the product is odd is if all four digits are odd. The odd digits are 1, 3, 5, 7, and 9, offering 5 choices for each digit. Thus, the total odd-digit combinations for four-digit numbers is (5^4 = 625). Therefore, the number of four-digit numbers with an even product is (9000 - 625 = 8375). The fraction is then ( \frac{8375}{9000} = \frac{335}{360} ), which simplifies to approximately ( \frac{67}{72} ).

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What fraction of all 4 digits natural numbers have a product of their digits that is even?

To find the fraction of 4-digit natural numbers with a product of their digits that is even, we first need to determine the total number of 4-digit natural numbers. There are 9000 such numbers (from 1000 to 9999). Next, we consider the conditions for the product of digits to be even. For a number to have an even product of digits, at least one of the digits must be even. There are 5 even digits (0, 2, 4, 6, 8) and 5 odd digits (1, 3, 5, 7, 9). Therefore, the fraction of 4-digit natural numbers with an even product of digits is 5/10 * 9/10 * 9/10 * 9/10 = 3645/9000 = 809/2000.


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