No. 64 is not evenly divisible by six.
64/4 = 16 with no remainder. The answer is yes, it does.
Yes, it goes in 16 times (16x4=64)
27 is 3 to the 3rd power, and 64 is 2 to the 6th power, so the only number that goes into both evenly is one (1).
A "divisor" means it evenly divides the number in question, so no: 64/14 = 4.57142857...
One.
All of these numbers divide into 64 evenly: 1, 2, 4, 8, 16, 32, 64.
These whole numbers go evenly into 64: 1, 2, 4, 8, 16, 32, 64.
No. 64 is not evenly divisible by ten.
No. These are the numbers that divide evenly into 64: 1 2 4 8 16 32 and 64.
The largest number that will divide evenly into 64 with no remainder is 64.
Not evenly.
Not evenly.
No. 64 is not evenly divisible by six.
64
The HCF of 16 and 64 is 16
64/4 = 16 with no remainder. The answer is yes, it does.