1, 2, 4, 8, 16, 32, 64.
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No. 64 is not evenly divisible by six.
64/4 = 16 with no remainder. The answer is yes, it does.
Yes, it goes in 16 times (16x4=64)
27 is 3 to the 3rd power, and 64 is 2 to the 6th power, so the only number that goes into both evenly is one (1).
A "divisor" means it evenly divides the number in question, so no: 64/14 = 4.57142857...