If the discriminant of b2-4ac in the quadratic equation formula is less than zero then the equation will have no real roots.
Assuming the equation is 2b2+5b-35=0, the quadratic formula is one way to solve this equation. It can't be factored easily. Do not confuse the "b" variable in the formula given with the "b" in the related link. The values of a, b, & c are as follows to be used in the quadratic formula: a=2, b=5, c= -35. Placing these values in the quadratic formula gives: (-5+/- sqrt(52-4*2*(-35)))/(2*2). This yields variable b = (-5+/- sqrt(305))/4 or (-5+17.46425)/4 & (-5-17.46425)/4 = 3.11606 & -5.61606 which are the two roots of the given equation.
Per the formula in the related link, substitution into the formula yields (3*12)1/2, which is (36)1/2 or 6.
The square root of a polynomial is another polynomial that, when multiplied by itself, yields the original polynomial. Not all polynomials have a square root that is also a polynomial; for example, the polynomial (x^2 + 1) does not have a polynomial square root in the real number system. However, some polynomials, like (x^2 - 4), have polynomial square roots, which in this case would be (x - 2) and (x + 2). Finding the square root of a polynomial can involve techniques such as factoring or using the quadratic formula for quadratic polynomials.
Where pi (~ 3.1416) is represented by π, The formula C= πr2 yields the formula r2 = (C/π) therefore r = square root (C/π). ...which is the same as : r = (C/π)1/2.
The formula is pi X radius2 X height. Application of this formula yields a value of about 1.130973355 X 103 of the cubic units corresponding to the length unit for the radius and height.
Using your ICE table in doing equilibrium calculations of concentrations in chemistry yields a quadratic function. X = Vot +(1/2)at2 is an equation of kinematics in physics.
Assuming the equation is 2b2+5b-35=0, the quadratic formula is one way to solve this equation. It can't be factored easily. Do not confuse the "b" variable in the formula given with the "b" in the related link. The values of a, b, & c are as follows to be used in the quadratic formula: a=2, b=5, c= -35. Placing these values in the quadratic formula gives: (-5+/- sqrt(52-4*2*(-35)))/(2*2). This yields variable b = (-5+/- sqrt(305))/4 or (-5+17.46425)/4 & (-5-17.46425)/4 = 3.11606 & -5.61606 which are the two roots of the given equation.
A base
6CO2+6H2O ----yields(sunlight)---- C6H12O6+6CO2
pottasium bisulfate((HSO4)1-) K+ + (HSO4)1- yields KHSO4
When dissolved in water, an Arrhenius base yields hydroxide ions (OH⁻) as the only negative ions in solution. This is because Arrhenius bases are substances that increase the concentration of hydroxide ions in aqueous solutions.
When b^2=4ac the zero is at a single point. The parabola does not penetrate the x axis. This represents two zeros, both with the same value. Example: x^2+4x+4 yields two zeros, each at x=-2. Notice that b^2=16=4ac. So Bob's your uncle!
The word equation for the formula 2Mg O2 yields 2MgO would be: "Two magnesium atoms react with one oxygen molecule to produce two magnesium oxide compounds."
2.81169x10^-12 J
Per the formula in the related link, substitution into the formula yields (3*12)1/2, which is (36)1/2 or 6.
The reaction between liquid bromine (Br2) and nitrogen gas (N2) yields nitrogen tribromide (NBr3) formula. The balanced chemical equation for the reaction is: 3 Br2 + N2 -> 2 NBr3
2H+2H2O gives 2KOH+H2