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Assuming the equation is 2b2+5b-35=0, the quadratic formula is one way to solve this equation. It can't be factored easily. Do not confuse the "b" variable in the formula given with the "b" in the related link. The values of a, b, & c are as follows to be used in the quadratic formula: a=2, b=5, c= -35. Placing these values in the quadratic formula gives: (-5+/- sqrt(52-4*2*(-35)))/(2*2). This yields variable b = (-5+/- sqrt(305))/4 or (-5+17.46425)/4 & (-5-17.46425)/4 = 3.11606 & -5.61606 which are the two roots of the given equation.
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What is 24a plus b2 plus 3a plus 2b2?
24a + b2 + 3a + 2b2= 27a + 3b2
What is b2 plus 3b-5b plus 2b2?
We can combine the like terms. So the b2 can be combined with the 2b2 to give 3b2. Likewise the 3b plus the -5b gives -2b.Therefore, b2 + 3b - 5b + 2b2 = 3b2 - 2b.
Factor 2b2 plus 10b plus 12?
The Answer to this question is 9 (2B+4) and (1B+3)
Factor 3ab plus 3ac plus 2b2 plus 2bc?
3a(b+c)+2b(b+c)
How do you express x4 plus y4 if given x plus y equals a xy equals b?
(x + y)2 = x2 + 2xy + y2 So x2 + y2 = (x + y)2 - 2xy = a2 - 2b Then (x2 + y2)2 = x4 + 2x2y2 + y4 So x4 + y4 = (x2 + y2)2 - 2x2y2 = (a2 - 2b)2 - 2b2 = a4 - 4a2b + 4b2 - 2b2 = a4 - 4a2b + 2b2
What is 24a plus b2 plus 3a plus 2b2?
24a + b2 + 3a + 2b2= 27a + 3b2
How do you factor fully 'a4 plus 4b4?
(a2+2b2-2ab)(a2+2b2+2ab)
What is b2 plus 3b-5b plus 2b2?
We can combine the like terms. So the b2 can be combined with the 2b2 to give 3b2. Likewise the 3b plus the -5b gives -2b.Therefore, b2 + 3b - 5b + 2b2 = 3b2 - 2b.
Simplify 4a 2b a plus b?
= 4a2 + 2ab 2b2
Find the illegal values of b in the fraction 2b2 plus 3b-10 over b2-2b-8?
2b2 + 8 para b = -3
Factor 2b2 plus 10b plus 12?
The Answer to this question is 9 (2B+4) and (1B+3)
Factor 3ab plus 3ac plus 2b2 plus 2bc?
3a(b+c)+2b(b+c)
B to the second plus b to the second?
b2 + b2 = 2b2 (when terms are alike, just add them up)
How do you express x4 plus y4 if given x plus y equals a xy equals b?
(x + y)2 = x2 + 2xy + y2 So x2 + y2 = (x + y)2 - 2xy = a2 - 2b Then (x2 + y2)2 = x4 + 2x2y2 + y4 So x4 + y4 = (x2 + y2)2 - 2x2y2 = (a2 - 2b)2 - 2b2 = a4 - 4a2b + 4b2 - 2b2 = a4 - 4a2b + 2b2
Factor 3ab plus 3ac plus 2b squared plus 2bc?
3ab + 3ac + 2b2 + 2bc = 3a(b + c) + 2b(b + c) = (3a + 2b)(b + c)
How do you factor 12a3-5a2b-2b2?
do you mean 12a3 - 5a2b - 2b2 ?? = 12a3 + 8a2b - 3a2b - 2b2 then group 1st 2 terms and last 2 and use GCF = (12a3 + 8a2b) + ( - 3a2b - 2b2) = 4a2(3a + 2b) + (-b)(3a2 +2b) not much help, but that's all folks
What is the LCM of 2b2 and 6c3?
To find the least common multiple (LCM) of 2b^2 and 6c^3, we first need to factorize both terms. The prime factorization of 2b^2 is 2 * b * b, and the prime factorization of 6c^3 is 2 * 3 * c * c * c. To find the LCM, we take the highest power of each prime factor that appears in either term, which gives us 2 * 3 * b^2 * c^3 = 6b^2c^3. Therefore, the LCM of 2b^2 and 6c^3 is 6b^2c^3.
