The origin and infinitely many other points of the form (x, ax) where x is any real number.
The graph of ax + by = c is a straight line going through the points (0, c/b) and (c/a, 0).
It is a straight line with gradient -A/B and intercept C/B.
It is the graph of a quadratic equation of the formy = ax^2 + bx + c
When 'a' is positive in a quadratic function of the form (y = ax^2 + bx + c), the graph opens upwards. This means the vertex of the parabola is the lowest point on the graph, and as you move away from the vertex in either direction, the values of (y) increase.
The origin and infinitely many other points of the form (x, ax) where x is any real number.
That the function is a quadratic expression.
Any function of the form f(x) = ax + b, or any relation of the form Ax + By = C.This is the function that forms a line graphed. The slope of line can be taken out as C/A. * * * * * The above answer assumes that a line MUST be a straight line! Since the graph is a line, the domain must be an interval in the Real numbers. The interval may be finite, or infinite in one or both directions. In order that the graph does not have breaks in it the function must be continuous. Any such function will do.
It is a straight line with gradient -A/B and intercept C/B.
The graph of ax + by = c is a straight line going through the points (0, c/b) and (c/a, 0).
It is the graph of a quadratic equation of the formy = ax^2 + bx + c
There is not a special name since the graph can represent any function of the form y = (ax + b)2n where a and b are any real constants and n is any positive integer.
When 'a' is positive in a quadratic function of the form (y = ax^2 + bx + c), the graph opens upwards. This means the vertex of the parabola is the lowest point on the graph, and as you move away from the vertex in either direction, the values of (y) increase.
y = ax + b
ax + by = cThe graph if that equation is a straight line whose slope is (-a/b)and whose y-intercept is (c/b).
The parent function of the exponential function is ax
y=ax+b