The origin and infinitely many other points of the form (x, ax) where x is any real number.
Where are the points!
there are 6 lines can pass through 4 noncollinear points.
A chord and the circle's diameter is its largest chord
Neither secant nor tangent pass through the center of a circle. A secant passes through one point on the circle and the tangent passes through two points on a circle.
Slope, m, equals (y2-y1)/(x2-x1). Slope is (8-2)/(8-2) or 1.
Well, honey, if you're looking for a function that passes through the points (2, 15) and (3, 26), you're talking about a linear function. The slope of this function would be 11 (rise of 11 over run of 1), so the equation would be y = 11x + b. To find the y-intercept, plug in one of the points, let's say (2, 15), and solve for b. So, the function that passes through those points is y = 11x + 4.
Test it by the vertical line test. That is, if a vertical line passes through the two points of the graph, this graph is not the graph of a function.
Where are the points!
The slope of a line that passes through two points is (difference in y) / (difference in x).
It is a line that passes through or nearly passes through the plotted points on the coordinated grid.
y - 2 = 0
there are 6 lines can pass through 4 noncollinear points.
Write the equation of the line that passes through the points (3, -5) and (-4, -5)
Since there are no "following" points, none of them.
It is a chord.
A chord and the circle's diameter is its largest chord
They are the poles.