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Q: What happens when you double the height of a cone have on the volume if radius remains the same?

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Double its height or increase its radius by a factor of sqrt(2) = 1.4142 (approx) or some combination of changes to he height and radius.

The volume decreases!

it will increase more if you double the radius because the dimensions multiply and the curved surface has less area to cover as its height decreases and width increases

Nothing - if you double the radius you will get the diameter. The area of the circle will remain the same

Your diameter is double the radius. So the diameter is 6

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It depends on whether the height remains unchanged or increases in the same proportion as the radius.

Since the volume of a cone is proportional to the square of the radius (look at the formula), double the radius would mean four times the volume.

Double its height or increase its radius by a factor of sqrt(2) = 1.4142 (approx) or some combination of changes to he height and radius.

The volume decreases!

it will increase more if you double the radius because the dimensions multiply and the curved surface has less area to cover as its height decreases and width increases

Nothing - if you double the radius you will get the diameter. The area of the circle will remain the same

If you notice the formulas you will see that the height and the radius are multiplied by 2, both of them. When you multiplied these together it will be like multiplying 2x2.

Your diameter is double the radius. So the diameter is 6

the volume changes as radius squared and linear with height, so tripling radius and double of height gives 3 x 3 x 2 = 18 times more volume

the area doubles. for example: the radius is 2. so the area is 4pi. then double the original radius of 2 to 4 and the area is 8pi. 8pi is double 4pi.

It remains the same or increases in surface area.

The original volume is multiplied by 27.