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Answer = 2690.9776 ft21 ft = .3048 m1 ft2 = .0929 m21 m2 = 10.7639 ft2250 m2 = 2690.9776 ft2
Suppose the two masses are m1 and m2. Their initial velocities are u1 and u2 and final velocities are v1 and v2. Then, using conservation of momentum. m1*u1 + m2*u2 = m1*v1 + m2*v2 Both m1 and m2 are given. Their initial velocities u1 and u2 are given and one of the two final velocities v1 and v2 is given which leaves only one unknown. So substitute all those values and calculate away.
Let us suppose we are plotting y vs x and obtain a straight line. Then we pick a set of two coordinates, x1,y1 and x2,y2 The slope, M, is then given by the equation M (y2-y1)/(x2-x1) If we apply this to a force vs mass graph, we obtain the expression M (F2-F1)/(m2-m1),but F ma according to Newton's second law, where a is the acceleration, which leads to (m2a2-m1a1)/(m2-m1), but if a2 a1 a, as it will if the line is straight, then M a(m2-m1)/(m2-m1) a, so the slope, M, of your graph is acceleration.
Condition of Parallelism: The Slope of two (lines) linear functions must be equal. i.e. m1=m2 Condition of perpendicularity : The product of slope of two (lines) linear functions must be equal to - 1. i.e. m1.m2=-1
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