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x+7 is greater than or equal to 2

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13y ago

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What are at least five inequality solutions to x-3?

x - 3 is not an inequality.


How is solving an inequality different from solving an equation?

In solving an inequality you generally use the same methods as for solving an equation. The main difference is that when you multiply or divide each side by a negative, you have to switch the direction of the inequality sign. The solution to an equation is often a single value, but the solution to an inequality is usually an infinite set of numbers, such as x>3.


Which lists all the integer solutions of the inequality of 3?

The question cannot be answered since it contains no inequality.


How do you solve an inequality when using the distributive property?

You solve an inequality in the same way as you would solve an equality (equation). The only difference is that if you multiply or divide both sides of an inequality by a negative number, you must reverse the inequality sign. Thus, if you have -3x < 9 to find x, you need to divide by -3. That is a negative number so -3x/(-3) > 9/(-3) reverse inequality x > -3


What is the inequality Negative three times a number increased by seven is less than negative 3?

-3x + 7 < -3 -3x < 4 x > -(4/3) ■


What is the name for two inequalities written as one inequality?

The name for two inequalities written as one inequality is a "compound inequality." This format expresses relationships involving two conditions simultaneously, often using "and" or "or" to connect them. For example, the compound inequality (3 < x < 7) combines two inequalities, (3 < x) and (x < 7).


What number is a solution of the inequality?

To determine a solution to an inequality, you need to specify the inequality itself. Solutions vary depending on the inequality's form, such as linear (e.g., (x > 3)) or quadratic (e.g., (x^2 < 4)). Once the inequality is provided, you can identify specific numbers that satisfy it. Please provide the inequality for a precise solution.


What happens if you multiply or divide an inequality by a negative number?

The inequality sign changes direction. So 2<3 Multiply by -2 and you get -4>-6 (similarly with division).


Why must you flip the inequality symbol when you divide by a negative number?

For the same reason you must flip it when you multiply by a negative number. An example should suffice. 2 < 3 If you multiply by -1, without switching the sign, you get: -2 < -3, which is wrong. Actually, -2 > -3. Look at a number line if you are not sure about this - numbers to the left are less than numbers further to the right. Dividing by a negative number is the same as multiplying by the reciprocal, which in this case is also negative. These signs are strictly the "Greater than" and "Less than" signs. The inequality sign is an = with a / stroke through it. If you divide an inequality by -1 it remains an inequality.


How do you solve and inequality with two signs?

Split it into two parts, solve each part as if it had an "=" sign instead of an inequality. Ex: -6<3x+2<12 -6<3x+2; -8<3x; -8/3<x Other side-- 3x+2<12; 3x<10; x<10/3 Then put them back together. -8/3<x<10/3 *Make sure you remember to switch the direction of the inequality symbol if you are dividing by a negative number.*


How do you solve an inequality with a negative coefficient?

The easiest way is to "flip" the inequality symbol end divide by the negative number:Example:6 < 3 - 3s6 - 3 < 3 - 3s -33 < -3s Method a) Divide by negative coefficient and flip the inequality symbol3/-3 > -3s/-3-1 > s or s< -13 < -3s Method b) Full algorithm, eliminate -3s by adding 3s on both sides3 +3s < -3s + 3s3 + 3s < 03 - 3 + 3s < 0 -33s < -33s/3 < -3/3s < -1 Looks familiar? So basically if you perform the full algorithm (method b) you can understand why we flip the inequality symbol when we have to eliminate a negative coefficient but it is faster just to flip the symbol (method a)


When do you switch the inequality sign?

Whenever you multiply (or divide) both sides an inequality by a negative number. Example: 3 &lt; 5, therefore -3 &gt; -5 -2x &lt; 10 becomes (by multiplying by -1/2): x &gt; 5 x(x+1) &gt; 0 In this type of inequality, you can divide both sides by x, but you have to consider the two cases, that x &gt; 0 and that x &lt; 0.