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The sum of two consecutive odd integers is -8 What are the integers?
The integers are -5 and -3: Where the first integer is x (and the second is x+2) x+(x+2) = -8 x+x+2 = -8 2x + 2 = -8 2x = -10 x = -5 and x+2 = -3
What is -5 x 2 of integers?
It is -10
What is the sum of the integers from 5 to 500?
The formula to sum a series of numbers is: sum = 1/2 x number_of_numbers x (first_number + last_number) So to sum the integers 5 to 500: From 5 to 500 there are 500 - 5 + 1 = 496 integers, so sum = 1/2 x 496 x (5 + 500) = 125240
Twice the smallest of three consecutive integers is five more than the largestfind the integers?
7, 8, 9 Let x be the smallest of the three integers; thus, the integers are x, x+1, x+2. From the problem, we get: 2x=(x+2)+5=x+7 2x-x=7 x=7
What is -x plus 5 factorised?
-(x-5) When you take the integers out right behind the "-" is a 1. so when you expand it will equal -x+5
How do you multiply integers with different signs?
To multiply two integers with different signs, multiply them together as though both were positive and then make the result negative.Examples:-2 x 5 → 2 x 5 = 10, made negative → -10⇒ -2 x 5 = -103 x -4 → 3 x 4 = 12, made negative → -12⇒ 3 x -4 = -12To multiply two integers of the same sign together, ignore the sings and just multiply them as positive numbers.-2 x -5 → 2 x 5 = 10 ⇒ -2 x -5 = 103 x 4 = 12These rules apply to all numbers, not just integers.
What is the sum of the integers from 5 to 500?
The formula to sum a series of numbers is: sum = 1/2 x number_of_numbers x (first_number + last_number) So to sum the integers 5 to 500: From 5 to 500 there are 500 - 5 + 1 = 496 integers, so sum = 1/2 x 496 x (5 + 500) = 125240
The sum of three consecutive odd integers is the same as five times the greatest of these integers find the smallest and the largest of these integers?
x + (x + 2) + (x + 4) = 5 (x + 4) so 3x + 6 = 5x + 20 ie -2x = 14 so x = -7 and integers are -7, -5 and -3 Sneaky!
Twice the smallest of three consecutive integers is five more than the largestfind the integers?
7, 8, 9 Let x be the smallest of the three integers; thus, the integers are x, x+1, x+2. From the problem, we get: 2x=(x+2)+5=x+7 2x-x=7 x=7
What is -x plus 5 factorised?
-(x-5) When you take the integers out right behind the "-" is a 1. so when you expand it will equal -x+5
The larger of 2 positive integers is 5 more than twice the smaller integer The product of the integers is 52 find the integers?
y=2x+5 xy=52 x(2x+5)=52 2x2+5x-52=0 (2x+13)(x-4)=0 x=-6.5 or x=4 Since you specified positive integers, x=4. y=2*4+5=13 So, the two numbers are 13 and 4.
What is the name for 2 given integers that combine to be zero?
Integers that add to zero (like 3 and -3 or 5 and -5) are called additive inverses. The general formula for an additive inverse is x + (-x) = 0, where x and (-x) are additive inverses.
What is the greatest of 5 consecutive integers if the sum of these integers equals 185?
(x) + (x-1) + (x-2) + (x-3) + (x-4) = 185 5x - 10 = 185 5x = 195 x = 39
How do you find three consecutive integers that have a sum of -12?
X + (X + 1) + (X + 2) = - 12 3X + 3 = - 12 3X = - 15 X = - 5 ------------ - 5 + ( - 5 + 1) + (- 5 + 2) = - 12 - 5 + ( - 4) + ( - 3) = -12 - 12 = -12 ----------------so, ( - 3, - 4, - 5 ) are the three consecutive integers
Solve for x x over 4 - 5 over 8 equals x plus 316?
Find two consecuitive integers whose sum is 89. To solve this problem, let x be the smaller of these integers. What is the larger of these two consecutive integers? In terms of x, write a formula that represents the sum of these two consecutive integers.
When the smaller of two consecutive integers is added to five times the larger the result is 53 find the integers?
x+5(x+1)=53 6x+5=53 6x=48 x=8 numbers=8 and 9
What is the product of -7 and -5?
-2
