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Twice the smallest of three consecutive integers is five more than the largestfind the integers?
Wiki User
∙ 14y ago
7, 8, 9
Let x be the smallest of the three integers; thus, the integers are x, x+1, x+2. From the problem, we get:
2x=(x+2)+5=x+7
2x-x=7
x=7
Wiki User
∙ 14y ago
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What are 3 consecutive integers such that twice the smallest is 12 more than the largest?
-- Call the three consecutive integers (x-1), x, and (x+1).-- Twice the smallest is 2(x-1) or (2x-2).-- 12 more than the largest is (x+1)+12 or (x+13).-- These are equal, so2x - 2 = x + 13Subtract 'x' from each side of the equation:x - 2 = 13Add 2 to each side:x = 15 .-- The smallest of the three numbers is (x-1) = 14.-- The three consecutive integers are 14, 15, and 16.-- Twice the smallest is 28.-- 28 is 12 more than 16.QED, man, QED !
Whats the answer to Find three consecutive even integers such that the sum of the smallest and twice the second is 20 more than the third?
Let the smallest integer be x. Since the consecutive even integers differ by 2, we havex + 2(x + 2) = (x + 4) + 203x + 4 = x + 24 (subtract x and 4 from both sides)3x - x - 4 + 4 = x - x - 4 + 242x = 20 (divide by 2 to both sides)x = 10Thus, the three consecutive even integers are 10, 12, and 14.
Find two consecutive integers such that the larger is nine more than twice the smaller?
-10 and -11.
What are two consecutive odd integers that when twice the larger is added to the small the result is 169?
55 and 57
The sum of an integer and twice the next consecutive integer is 29. What are the integers?
9 and 10 9 + 2(10) = 29
Five times the smallest of three consecutive even integers is 10 more than twice the largest. find the integers?
5872345098234783904672083946728390752430689723409687298290843 theres your answer
Find 3 consecutive integers such that twice the smallest is 12 more than the largest?
They are (14, 15, 16).
The sum of three consecutive even integers is fourteen less than twice the smallest of these integers. What is the smallest and greatest integers?
three consecutives numbers: a = smallest a+2 a+4 14 less = -14 than twice the smallest = 2a so... a+a+2+a+4=-14+2a 3a+6=-14+2a 3a-2a=-14-6 a=-20 answer: smallest = -20 greatest = -16
What are 3 consecutive integers such that twice the smallest is 12 more than the largest?
-- Call the three consecutive integers (x-1), x, and (x+1).-- Twice the smallest is 2(x-1) or (2x-2).-- 12 more than the largest is (x+1)+12 or (x+13).-- These are equal, so2x - 2 = x + 13Subtract 'x' from each side of the equation:x - 2 = 13Add 2 to each side:x = 15 .-- The smallest of the three numbers is (x-1) = 14.-- The three consecutive integers are 14, 15, and 16.-- Twice the smallest is 28.-- 28 is 12 more than 16.QED, man, QED !
If sum of three consecutive even integers is fourteen less than twice the smallest of these integers. What is the smallest integer?
Suppose the smallest integer is A. The next two even numbers are A+2 and A+4. Using the information supplied we can form an equation: 2A - 14 = A + A+2 + A+4 Rearranging: 2A - 14 = 3A + 6 -20 = A So the three integers are -20, -18 and -16.
Find three consecutive odd integers such that the sum of 7 times the smallest and twice the largest is -91?
98
Twice the smallest of three consecutive odd integers is seven more than the largest find the integers?
This equation works out to 2x = x + 11. This is because the three consecutive odd integers can be represented by x, x + 2, and x + 4. From the equation 2x - x = 11, so x = 11. Checking, 2 times 11 = 22 which is 7 more than 15. The three integers are 11, 13 and 15.
Whats the answer to Find three consecutive even integers such that the sum of the smallest and twice the second is 20 more than the third?
Let the smallest integer be x. Since the consecutive even integers differ by 2, we havex + 2(x + 2) = (x + 4) + 203x + 4 = x + 24 (subtract x and 4 from both sides)3x - x - 4 + 4 = x - x - 4 + 242x = 20 (divide by 2 to both sides)x = 10Thus, the three consecutive even integers are 10, 12, and 14.
Find the smallest of four consecutive even integers if twice the sum of the second and third integers is equal to the sum of the first and fourth integers increased by fourteen?
Since we know that the integers are even and consecutive, we can call them x, x+2, x+4, and x+6, with x being the smallest of the four. twice the sum of the second and third can be written as 2(x+2+x+4)=4x+12 the sum of the first and fourth increased by 14 is x+x+6+14=2x+20 Then we can solve 4x+12=2x+20-->2x=8-->x=4 4
Find two consecutive integers such that the larger is nine more than twice the smaller?
-10 and -11.
What are two consecutive odd integers that when twice the larger is added to the small the result is 169?
55 and 57
Find two consecutive odd integers if twice the larger increased by the smaller equals 85?
27, 29
