(x^2-2) (x^2+3x+5)= x^2(x^2+3x+5) -2(x^2+3x+5)= x^4 +3x^3 +5x^2 -2x^2 -6x -10= x^4 +3x^3 +3x^2 -6x -10
3x = x + 4 x = 2 3x2=6 2+4=6
When x=4, 3x-2 = 3(4)-2 = 12-2 = 10
3x + 4 = -23x = - 2 - 2x = -4/3* * *See if this doesn't work better:3x + 4 = -23x = -2 - 4 = -6x = -2Check:Substitute -2 for x, in the original equation.3(-2) + 4 = -6 + 4 = -2; thus, the answer is shown to be correct.
3x + 4y - 4 = 0 y = -2 3x + 4(-2) - 4 = 0 3x - 8 - 4 = 0 3x = 12 x = 4 (4,-2)
3x * (x - 4) = 3x*x - 3x*4 = 3x^2 - 12x.
3x * (x - 4) = 3x*x - 3x*4 = 3x^2 - 12x.
(x^2-2) (x^2+3x+5)= x^2(x^2+3x+5) -2(x^2+3x+5)= x^4 +3x^3 +5x^2 -2x^2 -6x -10= x^4 +3x^3 +3x^2 -6x -10
"2 over 3x equals 4" is an equation in a single variable, x.2/(3x) = 4 => 3x/2 = 1/4 => 3x = 2/4 = 1/2 => x = 1/6.
3x - 4 = -2 The answer is x=2/3
3x - 2 = 2x + 4 3x - 2x = 4 + 2 x = 6
(x-4)(3x-2)/(x-4) is equivalent to 3x-2 except when x=4.
3x = x + 4 x = 2 3x2=6 2+4=6
-3x - 2 = -6 -3x = -6 + 2 -3x = -4 -x = -4/3 x = 4/3 The absolute value is therefore 4/3.
When x=4, 3x-2 = 3(4)-2 = 12-2 = 10
3x3 + 6x2 - 24x = 3x(x2 + 2x - 8) = 3x(x2 + 4x - 2x - 8) = 3x[ x(x + 4) - 2(x + 4) ] = 3x(x - 2)(x + 4)
3x + 4 = -23x = - 2 - 2x = -4/3* * *See if this doesn't work better:3x + 4 = -23x = -2 - 4 = -6x = -2Check:Substitute -2 for x, in the original equation.3(-2) + 4 = -6 + 4 = -2; thus, the answer is shown to be correct.