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(x^2-2) (x^2+3x+5)= x^2(x^2+3x+5) -2(x^2+3x+5)= x^4 +3x^3 +5x^2 -2x^2 -6x -10= x^4 +3x^3 +3x^2 -6x -10
3x = x + 4 x = 2 3x2=6 2+4=6
When x=4, 3x-2 = 3(4)-2 = 12-2 = 10
3x + 4 = -23x = - 2 - 2x = -4/3* * *See if this doesn't work better:3x + 4 = -23x = -2 - 4 = -6x = -2Check:Substitute -2 for x, in the original equation.3(-2) + 4 = -6 + 4 = -2; thus, the answer is shown to be correct.
3x + 4y - 4 = 0 y = -2 3x + 4(-2) - 4 = 0 3x - 8 - 4 = 0 3x = 12 x = 4 (4,-2)