-(3x+4)(x+2)
Yes. (Assuming that -3x2 is the best representation of 3x2 that this browser will allow.)
3x2 - 19x - 14 = 0 3x2 - 21x + 2x - 14 = 0 3x(x - 7) + 2(x - 7) = 0 (x - 7)(3x + 2) = 0 x - 7 = 0 or 3x + 2 = 0 x = 7 or x = -2/3
X + 4 is a factor of x^3 + 3x^2 - 10x - 24 along with (x + 2) and (x - 3)
3x2 + 2x + 2 = 0 Can not be factored. You can however solve it for x: 3x2 + 2x = -2 x2 + 2x/3 = -2/3 x2 + 2x/3 + 1/9 = -2/3 + 1/9 (x + 1/9)2 = -5/9 x + 1/9 = ±√(-5/9) x = -1/9 ± i√(5/9) x = -1/9 ± i√5 / 3 x = -1/9 ± 3i√5 / 9 x = (-1 ± 3i√5) / 9
Do you mean 3x2+10x-8 if so then it is (3x-2(x+4) when factored
It is: (-3x-4)(x+2) when factored
I guess that should be 3 times (x squared) minus 48: 3x2 - 48 = 3(x2 - 16) = 3(x + 4)(x - 4)
-3x2+10x-3 -(3x2-10x+3) -(3x-1)(x-3)
Set the equation equal to zero. 3x2 - x = -1 3x2 - x + 1 = 0 The equation is quadratic, but can not be factored. Use the quadratic equation.
3x2 + 10x + 3 = (x + 3)(3x + 1).
the answer is 60
If you mean: 27x2-90x+27 then divide all terms by 9 which is then 3x2-10x+3 And when factored it is: (3x-1)(x-3)
3x2 - 7x - 20 = (3x + 5)(x - 4)
3x2 -12x+24=-10x-20-3x2+6
3x2+13x-10 = (3x-2)(x+5) when factored
3x2+7-6 = (3x-2)(x+3) when factored